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3 years ago

Shannon is playing tennis. She swings her racket to hit the tennis ball and sends the ball flying in the same direction.

Physics

1 answer:

Gnoma [55]3 years ago

3 0

Answer:

she used force to swing her ball all way back

Explanation:

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alexandr1967 [171]

Answer:

its C. The north pole of one magnet attracts the south pole of another

Explanation:

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3 years ago

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One end of a 7-cm-long spring is attached to the ceiling. When a 5.4 kg mass is hung from the other end, the spring is stretched

mash [69]

Answer:

2.63 cm

Explanation:

Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension

Making c the subject of the formula then

$c=\frac {F}{y}$

Since F is gm but taking the given mass to be F

$c=\frac {5.4 kg}{4.3 cm}=1.2558139534883720930232558139534883720930$

By substitution now considering F to be 3.3 kg

$y=\frac {3.3 kg}{1.2558139534883720930232558139534883720930}=2.6277777777777 cm\approx 2.63 cm$

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3 years ago

A train travels 8.81 m/s in a -51.0° direction.

Amiraneli [1.4K]

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

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1 year ago

A 10-cm-long wire is pulled along a u-shaped conducting rail in a perpendicular magnetic field. the total resistance of the wire

Debora [2.8K]

In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.

Part a)

when we pull the rod with constant speed then power required will be product of force and velocity

here we will have

$P = F.v$

P = 4 W

v = 4 m/s

now we will have

$4 = F*4$

$F = 1N$

So external force required will be 1 N

PART B)

now in order to find magnetic field strength we can say

$P = \frac{v^2B^2L^2}{R}$

here we know that induced EMF in the wire is E = vBL

so power due to induced magnetic field is given by

$P = \frac{E^2}{R}$

$4 = \frac{4^2*B^2*0.10^2}{0.20}$

by solving above equation we will have

$B = 2.24 T$

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3 years ago

What is a type of motion of a cradle? <br>

katrin [286]

Answer:

<em>conservation of momentum and energy using a series of swinging spheres</em>

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2 years ago

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