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topjm [15]
3 years ago
12

An object falls for 7 seconds. How far does it fall?

Physics
1 answer:
aliina [53]3 years ago
5 0

Answer:

It depends on what the object is and what planet it is on and what the conditions are.

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: The maximum theoretical efficiency of a Carnot engine operating between reservoirs at the steam point and at room temperature
Hunter-Best [27]

Answer:

The value is   \eta  =  0.2145  or  21.45%

Explanation:

From the question we are told that

    The first reservoir is at steam point  T_s =  100^o C =  100 + 273 = 373 \ K  

    The  second reservoir is at room temperature T_r  =  20^o C = 293 \ K

Generally the  maximum theoretical efficiency of a Carnot engine  is mathematically evaluated as

     \eta  =  1- \frac{T_r}{T_s}

=>    1 - \frac{ 293}{373}

=>    \eta  =  0.2145

5 0
3 years ago
Init.
nikklg [1K]

Answer:

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015×10−34 when expressed in the unit J⋅s, which is equal to kg⋅m2⋅s−1, where the metre and the second are defined in terms of c and ΔνCs.

8 0
3 years ago
Read 2 more answers
I wonder if people that say that there ugly is to get attention (not to be mean...)​
alexandr1967 [171]
They do. mostly because they want validation from others
5 0
2 years ago
Read 2 more answers
What are the strength and direction of an electric field that will balance the weight of a 0.9 g plastic sphere that has been ch
Vladimir79 [104]
(a) The force exerted by the electric field on the plastic sphere is equal to
F=qE
where q=-3.4 nC=-3.4 \cdot 10^{-9} C is the charge of the sphere and E is the strength of the electric field. This force should balance the weight of the sphere:
F=mg =0.9 g
where m is the mass of the sphere and g is the gravitational acceleration.

Since the two forces must be equal, we have:
qE=mg
and so we find the intensity of the electric field
E= \frac{mg}{q}= \frac{0.9 \cdot 9.81 m/s^2}{3.4 \cdot 10^{-9} C} =2.6 \cdot 10^9 N/C

(b) Now let's find the direction of the field. The electric force must balance the weight of the sphere, which is directed downward, so the electric force should be directed upward. Since the charge is negative, the force is opposite to the electric field direction, and so the direction of the electric field is downward.
4 0
3 years ago
In the diagram, q1=+6.25 * 10^ -8 C. What is the potential difference when you go from point A to point B? Include the correct s
Nimfa-mama [501]

Answer:

Moving a unit "positive" test charge from A to B will result in a reduction in potential

V = K Q / R      potential at a point

V2 - V1 = K Q (1 / .4 - 1 / .15) = = k Q (.15 - .4) / .06 = -4.17 K Q

V2 - V1 = -4.17 * 9 & 10E9 * 6.25 E-8

V2 - V1 = -4.17 * 562.5 J/C

V = - 2346 Volts

7 0
3 years ago
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