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2 years ago

What is the slope of the line that passes through the points (-4, -2) and (-4, -22)? Write your answer in simplest form.

Mathematics

1 answer:

aliina [53]2 years ago

3 0

Answer:

Your answer is: Undefined

Use the slope formula to find the slope m .

Step-by-step explanation:

Hope this helped : )

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EMERGENCY!!!! 15-26 Please slove all of them it’s due tomorrow

DanielleElmas [232]

I don’t have the time to do this, but there is a app called Socratic where you can take a pic of your homework and it searches everything on google.

That’s how I got Brainly

5 0

2 years ago

The base of a triangle is nine centimeters longer than the perpendicular height. If the area of the triangle is 180 square centi

Rom4ik [11]

Answer:

The base is 24 cm long.

Step-by-step explanation:

Equations

Let's call

b= base of the triangle

h=height of the triangle

The base is 9 cm longer than the height, thus:

b = h + 9

The area of the triangle is:

$\displaystyle A=\frac{bh}{2}$

$\displaystyle A=\frac{(h+9)h}{2}$

And its value is 180:

$\displaystyle \frac{(h+9)h}{2}=180$

Multiplying by 2:

$(h+9)h=360$

Operating:

$h^2+9h-360=0$

Factoring:

$(h-15)(h+24)=0$

The only valid positive solution is:

h = 15 cm

And b = h + 9 = 24

b = 24 cm

The base is 24 cm long.

7 0

3 years ago

What is new equation if the function y=2^x is translated 5 units to the right and 1 unit down?

Alja [10]

2^(x-5) -1 should be it

4 0

2 years ago

Dexter has four different coins in his pocket. He randomly selects a coin from his pocket, replaces it, and selects another coin

skad [1K]

Answer:

Step-by-step explanation:

So what is the probability of the selecting the first coin? There are total of 4 different coins, so the probability of getting a dime is 1 out of 4, then he replace it, then again the probability stays the same, he still has 1 out 4 chance of getting a dime. So then it's just 1/4*1/4=1/16 :)

4 0

3 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.

$y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7$

Substitute these into the ODE to see everything checks out:

$2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14$

5 0

3 years ago