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alexira [117]
3 years ago
9

NEED HELP Solve.y=2x-64x-2y=14​

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

No solution

Step-by-step explanation:

Replace occurrences of y in 4x - 2y = 14 with 2x - 6

y = 2x - 6

4x - 2 (2x - 6) = 14

Simplify left side

y = 2x - 6

12 = 14

S<u>ince 12 is not equals to 14, There is no solution</u>

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Please help me. This is real confusing. ​
katrin2010 [14]

Answer:

1st problem: b) A=2500(1.01)^{12t}

2nd problem:  c) A=2500e^{.12t}

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

A=P(1+\frac{r}{n})^{nt}

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

A=2500(1+\frac{.12}{12})^{12t}

Time to clean up the inside of the ( ).

A=2500(1+.01)^{12t}

A=2500(1.01)^{12t}

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

A=Pe^{rt}

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

A=2500e^{.12t}.

6 0
3 years ago
Help please!!!!!!!!!!!!
matrenka [14]

Answer:

your answer is as follows

Step-by-step explanation:

5x+20=3x+60

2x=40

x=20

(equating the slopes)

8 0
2 years ago
What's the value of given expression :<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B8%20%5Ctimes%202%7D%20" id="TexForm
Drupady [299]

Answer:

\sqrt{8 \times 2}   \\ =  \sqrt{16}  \\  =  \sqrt{4 \times 4}  = 4 \\ thank \: you

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2 years ago
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Answer:-2-5÷4-1=-1

Step-by-step explanation:

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3 years ago
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olga nikolaevna [1]

Answer:

D

Step-by-step explanation:

because it seem to be correct

4 0
3 years ago
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