[ H+]=10-pH
it become
[H+]=0.1
Answer:
a. Neutral
b. Basic
Explanation:
To determine which of the salts are acidic, neutral or basci we should dissociate them and determine if the ions, can make hydrolysis to water.
KCl → K⁺ + Cl⁻
We need to know, where do the ions come from. In this case, K⁺ comes from the KOH which is a strong base and Cl⁻ comes from the HCl, a strong acid. In conclussion, both are the conjugate weak acid and base, respectively. They do not make hydrolysis, so this salt is neutral. No protons or hydroxides are given.
NaClO → Na⁺ + ClO⁻
The Na⁺ comes from the NaOH, it is the conjugate weak acid from a strong base, while the ClO⁻ comes from the HClO, a weak acid. This means that the ClO⁻ can react to water, to make hydrolysis. The equilibrium will be:
ClO⁻ + H₂O ⇄ HClO + OH⁻
We are giving hydroxides to medium, so the salt is basic.
Answer:
A. 0.000128 M is the solubility of M(OH)2 in pure water.
B. 
is the solubility of 
in a 0.202 M solution of 
.
Explanation:
A
Solubility product of generic metal hydroxide = 
S 2S
The expression of a solubility product is given by :
![K_{sp}=[M^{2+}][OH^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BM%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)
Solving for S:
0.000128 M is the solubility of M(OH)2 in pure water
B
Concentration of = 0.202 M
Solubility product of generic metal hydroxide =
S 2S
So, ![[M^{2+}]=0.202 M+S](https://tex.z-dn.net/?f=%5BM%5E%7B2%2B%7D%5D%3D0.202%20M%2BS)
The expression of a solubility product is given by :
Solving for S:
is the solubility of in a 0.202 M solution of .
Answer:
"El agua destilada, al no tener ninguna sal disuelta, no conduce la corriente eléctrica, no hay iones que la puedan conducir."
