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Elena L [17]
2 years ago
11

Qeoahefji

Chemistry
1 answer:
ICE Princess25 [194]2 years ago
4 0

Answer:

B. Experiments

Explanation:

conducting an experiment is an example of a research method while the other choices are not.

Hope I was able to help you!

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Why are significant figures rules for calculations more important in science than in math class?
inysia [295]

Answer:

The importance of significant figures

As stated before, it is important within the science fields that you are not more precise or accurate than the least accurate or precise number. In science, it is generally agreed upon that the last number digit in any figure is filled with uncertainty.

Explanation:

4 0
3 years ago
What is the molarity of 10g of carbon in a 500L solution?
Zolol [24]

Answer:

Molarity is the number of moles in a liter of a substance.

Molarity= Mole/volume

Mass= 10g

Molar mass of Carbon=12g

To calculate the mole we use the formula: mole= mass/molar mass

Mole = 10g/12g

Mole = 0.83

Molarity= 0.83/500 =0.0017moles per liter

5 0
3 years ago
What are the names of the stable forms of oxygen?
zloy xaker [14]

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

5 0
3 years ago
A rectangular corral of widths Lx = L and Ly = 2L contains seven electrons. What is the energy of (a) the first excited state, (
DiKsa [7]

Answer:

See explaination

Explanation:

The invariant mass of an electron is approximately9. 109×10−31 kilograms, or5. 489×10−4 atomic mass units. On the basis of Einstein's principle of mass–energy equivalence, this mass corresponds to a rest energy of 0.511 MeV.

Check attachment for further solution to the exercise.

3 0
3 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
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