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lara [203]
3 years ago
15

Find the volume of a rectangular prism with a length of 3 ¾ meters, a width of 1 ½ meters, and a height of 2 meters. A. 11.25 cu

bic meters B. 12 cubic meters C. 7.25 cubic meters D. 15 cubic meters
Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
V = LWH

Change the dimensions to decimal numbers.

L = 3.75 m
W = 1.5 m
H = 2 m

V = (3.75 m)(1.5 m)(2 m)

V = 11.25 m^3
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The answer to your question is true
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3 years ago
A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.
GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: A(x) = x^2 but we aim to find \frac{dA}{dt}. But we can use the chain rule to pull out that dA/dt. Doing so gives us:

\frac{dA}{dt} = \frac{dA}{dx} \times \frac{dx}{dt}.

Now, \frac{dA}{dx} = 2x (by the power rule and \frac{dx}{dt} = 3.

But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.

So, finally, we see that:

\frac{dA}{dt} = 2(7) \times 3 = 14 \times 3 = 42.

7 0
4 years ago
what is the scale factor of triangle UVW to triangle XYZ where uvw has side Lengths 3,4,2, and XYZ has lengths 14,28,21
alekssr [168]

Answer: 7

Step-by-step explanation:

Given:  Triangle UVW map to triangle XYZ where Triangle UVWhas side Lengths 3,4,2, and triangle XYZ has lengths 14,28,21.

We know that the scale factor between two similar figures is the the ratio of the corresponding side of image to the original figure.

Let k be the scale factor.

Then,

k=\frac{21}{3}=\frac{14}{2}=\frac{28}{4}=7\\\\\Rightarrow\ k=7

Hence, the scale factor = 7

8 0
3 years ago
What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
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