Answer:
14.8005 Joules
Explanation:
This question is describing the calculation for the amount of heat (Q) a substance absorbs or releases. The amount of heat, Q, is calculated using the formula:
Q = m × c × ∆T
Where;
Q = amount of heat (Joules)
m = mass of substance (g)
c = specific heat of substance (J/g°C)
∆T = change in temperature of substance i.e. final temperature - initial temperature (°C).
According to this question, the following expression is given:
q = 0.75 g x 0.897 J/g•°C x 22°C
To calculate this further, this will equal to: 14.8005
This means that the amount of heat, q, absorbed or released by that substance is equal to 14.8005 Joules.
The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,
mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
mass of nitrogen = 0.602 g N₂
Therefore, 0.602 g of nitrogen will be required for he reaction.
11 L because you just need to use a pie chart
Answer: ![Ne:1s^22s^22p^6](https://tex.z-dn.net/?f=Ne%3A1s%5E22s%5E22p%5E6)
![Li:1s^22s^1](https://tex.z-dn.net/?f=Li%3A1s%5E22s%5E1)
![N:1s^22s^22p^3](https://tex.z-dn.net/?f=N%3A1s%5E22s%5E22p%5E3)
![S:1s^22s^22p^63s^23p^4](https://tex.z-dn.net/?f=S%3A1s%5E22s%5E22p%5E63s%5E23p%5E4)
![Sc:1s^22s^22p^63s^23p^64s^23d^1](https://tex.z-dn.net/?f=Sc%3A1s%5E22s%5E22p%5E63s%5E23p%5E64s%5E23d%5E1)
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies.
The electronic configuration for given elements is as follows:
![Ne:10:1s^22s^22p^6](https://tex.z-dn.net/?f=Ne%3A10%3A1s%5E22s%5E22p%5E6)
![Li:3:1s^22s^1](https://tex.z-dn.net/?f=Li%3A3%3A1s%5E22s%5E1)
![N:7:1s^22s^22p^3](https://tex.z-dn.net/?f=N%3A7%3A1s%5E22s%5E22p%5E3)
![S:16:1s^22s^22p^63s^23p^4](https://tex.z-dn.net/?f=S%3A16%3A1s%5E22s%5E22p%5E63s%5E23p%5E4)
![Sc:21:1s^22s^22p^63s^23p^64s^23d^1](https://tex.z-dn.net/?f=Sc%3A21%3A1s%5E22s%5E22p%5E63s%5E23p%5E64s%5E23d%5E1)