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liraira [26]
4 years ago
15

There are four hundred participants in the local Thanksgiving 5K race. If 51% of the participants are female, what is the ratio

of female participants to male participants?​
ITS FOR MATH. I ACCIDENTALLY CLICKED CHEMISTRY
Chemistry
1 answer:
Paha777 [63]4 years ago
5 0

Answer:

51:49 is the ratio of female participants to male participants.

Explanation:

Percentage of females in the race = 51 %

Percentage of males in the race = 100% - 51 % = 49%

Total participants in race = 400

Number of women participants = 51% of 400=\frac{51}{100}\times 400=204

Number of men participants  = 49% of 400=\frac{49}{100}\times 400=196

Ratio of female participants to male participants :

\frac{204}{196}=\frac{51}{49}=51:49

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General Formulas and Concepts:

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

0.200 mol H₂S

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<u>Step 3: Convert</u>

  1. Set up:                    \displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})
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<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

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