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Zanzabum
3 years ago
14

Prove that the curve a(t) = (cost, sin 2t, cos 2t) is regular on R and that it self-intersects at (1,0,1). Check the self-inters

ection part by using algebra and also by using Geofte
Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

The function a (t) is a vector function composed of the component functions a_ {1} (t) = cost, a_ {2} (t) = sin2t and a_ {3} (t) = cos2t. How a_ {1} (t), a_ {2} (t), a_ {3} (t) are infinitely derivable functions in R, so they are regular functions in R.

Now, fort = 0, you have to a (0) = (cos (0), sin2 (0), cos2 (0)) = (1, 0, 1). How the functions a_ {1} (t), a_ {2} (t), a_ {3} (t) are periodic functions with period 2 \pi, the vector function a (t) will take the same point (1, 0 , 1) at t = 2n\pi, n = 0, 1, 2, 3, ... then the vector function is auto-intercepted

Step-by-step explanation:

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For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

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y = \frac {1} {4} x + 2

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