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siniylev [52]
3 years ago
13

Lines AB and CD and are parallel. Find the measures of the three angles in triangle ABF.

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:    ∠B = 42°   ∠A = 23°  ∠F = 115°

Step-by-step explanation:

∠B≅∠C  alternate interior angles  42°

  ∠CDF is supplementary to ∠CDE,

so m∠CDF = 23°  and ∠FAB≅∠CDF so m∠FAB= 23°

<em>also ∠A ≅ CDE  corresponding angles  157° ∠FAB is suplementary to ∠A </em>

<em>so 180 - 157 = 23 gives the m∠FAB</em>

The sum of the angles of a triangle is 180°, so m∠AFB = 180 -(23 +42)

180- 65 = 115 = m∠F

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So if we were to set up a proportion we could say:

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We are given that s=4m and r=13m so:

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α=720/(13π) m  which is approximately:

α≈17.63°

Which is why radians are often used, because in radians...

α=[720/(13π)](π/180)

α=4/13 rads

Or the arc length in radians is simply expressed as:

s=rα

α=s/r  (which is much neater :P) then it is plain to see that:

α=4/13  rads


7 0
3 years ago
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How many linear pairs are formed when two non parallel lines intersect?
Art [367]
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6 0
3 years ago
Need help for number 4 please
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Answer:

Step-by-step explanation:

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  BN = 9 cm                                           m∠W = 82°

b) TW = FN                                        e) m∠B = m∠S

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36 +115 + ∠S = 180

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3y - 21  = 18

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