Answer:
B. ( –3, –4)
C. ( 4, 17 )
Step-by-step explanation:
Function: y = 3x + 5
Using method of elimination
A. (2, –1)
x = 2, y = -1
-1 = 3 (2) + 5
-1 ≠ 11
This option is incorrect!
B. ( –3, –4)
x = -3, y = -4
-4 = 3 (-3) + 5
-4 = - 9 + 5
-4 = -4
This option is correct!
C. ( 4, 17 )
x = 4, y = 17
17 = 3 (4) + 5
17 = 12 + 5
17 = 17
This option is correct!
D. ( 3, 8 )
x = 3, y = 8
8 = 3 (3) + 5
8 = 9 + 5
8 = 14
This option is incorrect!
Answer:
y = 4 sin(t/2 + 4π/3) − 2
Step-by-step explanation:
General form:
y = a sin(2π/T t)
Given a = 4 and T = 4π:
y = 4 sin(2π/(4π) t)
y = 4 sin(t/2)
Add horizontal shift of -4π/3 and vertical shift of -2:
y = 4 sin(t/2 − (-4π/3)) − 2
y = 4 sin(t/2 + 4π/3) − 2
Answer:
B and C work. A and D do not.
Step-by-step explanation:
This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.
A]
5n + 6
Let n = 1
5(1) + 6
5 + 6= 11
However there is trouble beginning with n = 2
5*2 + 6
10 + 6
16 All you need is one wrong answer and the choice is toast. So A won't work.
================
Try D
6(n - 1)+ 5
n=0
6*(-1) + 5
-6 + 5
- 1
And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse. D is not one of the answers.
=============
B
Let n = 1
6(1) + 5
6 + 5
11 The first term works.
n = 2
6*(2) + 5
12 + 5
17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.
n = 3
6*(3) + 5
18 + 5
23 And this also works. I'll let you deal with n = 4
========
C
n = 0
6(0 + 1) + 5
6*1 + 5
6 + 5
11
n = 1
6(1 + 1) + 5
6*2 + 5
12 + 5
17 which works.
So C is an answer.
Answer:
the answer to the problem is h=7
Step-by-step explanation:
Explanation is in the attachment
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