Answer:
There are 4 Aluminum atoms in 4Al(OH)3.
Answer:
a) 
b) 
Explanation:
From the exercise we know:
;
; 
;
; 
The formula for average velocity is:

a) 
The formula for average acceleration is:

b) 
The number of charge drifts are 3.35 X 10⁻⁷C
<u>Explanation:</u>
Given:
Potential difference, V = 3 nV = 3 X 10⁻⁹m
Length of wire, L = 2 cm = 0.02 m
Radius of the wire, r = 2 mm = 2 X 10⁻³m
Cross section, 3 ms
charge drifts, q = ?
We know,
the charge drifts through the copper wire is given by
q = iΔt
where Δt = 3 X 10⁻³s
and i = 
where R is the resistance
R = 
ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm
So, i = 
q = 
Substituting the values,
q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02
q = 3.35 X 10⁻⁷C
Therefore, the number of charge drifts are 3.35 X 10⁻⁷C
Answer:
Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.
Hence, for series combination of resistances,
R
s
=2R
And for parallel combination of resistances,
R
p
=
2
R
Now, heat produced when they first connected in series is
H
s
=
R
s
V
2
where, V is voltage supplied to the heater.
H
s
=
2R
V
2
.....................................(1)
heat produced when they first connected in series is
H
p
=
R
p
V
2
H
p
=
2
R
V
2
H
p
=
R
2V
2
............................................(2)
From (1) and (2), we get
H
p
H
s
=
R
2V
2
2R
V
2
⇒
H
p
H
s
=
4
1
PITCH
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