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JulsSmile [24]
4 years ago
12

According to the periodic table, how many protons are in the nucleus of one

Physics
2 answers:
Y_Kistochka [10]4 years ago
7 0

Answer:

the answer is c

Explanation:

vodomira [7]4 years ago
3 0

Answer:

C.

Explanation:

The atomic number is derived from the number of protons in the atomic nucleus. The atomic number of bromine is 35, therefore it has 35 protons in its atoms.

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How many aluminum atoms are in the following compound?<br> 4 Al(OH)3
vovikov84 [41]

Answer:

There are 4 Aluminum atoms in 4Al(OH)3.

3 0
3 years ago
A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s
Bogdan [553]

Answer:

a) v=20.3m/s

b) a=2.35m/s^2

Explanation:

From the exercise we know:

x_{1}=30m; v_{1}=10m/s; t_{1}=3s

x_{2}=375m; v_{2}=50m/s; t_{2}=20s

The formula for average velocity is:

v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}

a) v=\frac{375m-30m}{20s-3s}=20.3m/s

The formula for average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}

b) a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2

4 0
3 years ago
A potential difference of 3.00 nV is set up across a 2.00 cm length of copper wire that has a radius of 2.00 mm. How much charge
Anvisha [2.4K]

The number of charge drifts are 3.35 X 10⁻⁷C

<u>Explanation:</u>

Given:

Potential difference, V = 3 nV = 3 X 10⁻⁹m

Length of wire, L = 2 cm = 0.02 m

Radius of the wire, r = 2 mm = 2 X 10⁻³m

Cross section, 3 ms

charge drifts, q = ?

We know,

the charge drifts through the copper wire is given by

q = iΔt

where Δt = 3 X 10⁻³s

and i = \frac{V}{R}

where R is the resistance

R = \frac{pL}{r^{2} \pi }

ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm

So, i = \frac{\pi(r)^{2}V  }{pL}

q = \frac{\pi(r^{2} )Vt }{pL}

Substituting the values,

q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02

q = 3.35 X 10⁻⁷C

Therefore, the number of charge drifts are 3.35 X 10⁻⁷C

3 0
3 years ago
1 point
marta [7]

Answer:

Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.

Hence, for series combination of resistances,

R

s

=2R

And for parallel combination of resistances,

R

p

=

2

R

Now, heat produced when they first connected in series is

H

s

=

R

s

V

2

where, V is voltage supplied to the heater.

H

s

=

2R

V

2

.....................................(1)

heat produced when they first connected in series is

H

p

=

R

p

V

2

H

p

=

2

R

V

2

H

p

=

R

2V

2

............................................(2)

From (1) and (2), we get

H

p

H

s

=

R

2V

2

2R

V

2

⇒

H

p

H

s

=

4

1

7 0
3 years ago
Measure of how high or low a sound is
katovenus [111]
PITCH
please mark brainliest!!!
4 0
3 years ago
Read 2 more answers
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