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alukav5142 [94]
3 years ago
10

The average distance from the sun to Pluto is approximately 6.10 × 109 km. How long does it take light from 

Physics
1 answer:
Scorpion4ik [409]3 years ago
3 0
V= \frac{S}{t}
t= \frac{S}{V}<u />
t= \frac{S}{c}
t= \frac{6.1*10^{12}}{299792458}
t=20347.4098071s

It takes 20347.4098071s for light from the sun to reach Pluto.
The 6.1*10^9 is replaced by 6.1*10^12 on line 4 because we convert the distance from km to m. 
c = speed of light. If a different value was given in the previous question then use that instead of the value I used to do the final calculation.
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In Newton’s second law, if the net force acting on object doubles. The object’s Will also double
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Answer: Explanation:

If the net force on an object is doubled, its acceleration will double If the mass of an object is doubled, the acceleration will be halved .

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A particle moves along a straight path through a displacement d = 2.5i + cj while a force F = 8.5i + -8.5j acts on it. The displ
Zanzabum

Answer:

Explanation:

Work is defined as the scalar product of force and distance

W=F•d

Given that

F = 8.5i + -8.5j. +×-=-

F=8.5i-8.5j

d = 2.5i + cj

If the work in the practice is zero, then W=0

therefore,

W=F•ds

0=F•ds

0=(8.5i -8.5j)•(2.5i + cj)

Note that

i.i=j.j=k.k=1

i.j=j.i=k.i=i.k=j.k=k.j=0

So applying this

0=(8.5i -8.5j)•(2.5i + cj)

0= (8.5×2.5i.i + 8.5×ci.j -8.5×2.5j.i-8.5×cj.j)

0=21.25-8.5c

Therefore,

8.5c=21.25

c=21.25/8.5

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Which term is applied to an object through which light passes?
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D

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A 0.250 kg fan cart accelerates at 24 cm/ s^2 for 4.5 seconds. what is the net force (fan thrust minus drag and friction) on the
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Answer:

0.06 N

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Explanation:

m = mass of the fan cart = 0.250 kg

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Net force on the cart is given as

F = ma

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v = final velocity of the cart

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Using the equation

v = v₀ + a t

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v = 1.08 m/s

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