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beks73 [17]
3 years ago
15

Find the conductivity of a conduit with a cross-sectional area of 0.60 cm2 and a length of 15 cm, given that its conductance G i

s 0.050 ohm-1.
.13 ohm -1cm -1
.030 ohm -1cm -1
1.3 ohm -1cm -1
13 ohm -1cm -1
Physics
1 answer:
marta [7]3 years ago
3 0
I guess the answer would be the third one !
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In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
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Answer:

Explanation:

Let the required velocity of rocket be v .

We shall use the formula of time dilation to find the velocity of rocket .

t = \frac{t'}{\sqrt{1-\frac{v^2}{c^2} } }

t = 430

t' = 38

430=\frac{38}{\sqrt{1-\frac{v^2}{c^2} } }

\sqrt{1-\frac{v^2}{c^2} } }=\frac{38}{430}

1-\frac{v^2}{c^2} = .0078

\frac{v^2}{c^2} =.9922

\frac{v}{c} = .996

v  = .996 x 3 x 10⁸ m /s

= 2.988 x 10⁸ m /s

B )

Kinetic energy of rocket

= 1/2 m v²

= .5 x 20000 x (2.988 x 10⁸ )²

= 8.9 x 10²⁰ J .

C )

This energy is 8.9 times the energy requirement of United states in the year 2005 .

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3 years ago
What are the four components that can be derived from a unit of blood?
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Within that unit of blood, you are going to have plasma, white blood cells, red blood cells, and platelets. 
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Amazon rectangular bar of low carbon steel A-36 is exposed to an axial strees of 150 MPa. What is the original length of the bar
kolbaska11 [484]

Answer:

1.8m

Explanation:

Let the Elastics of the steel ASTM-36 E = 200000 MPa

The strain of the bar when subjected to 150 MPa is

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Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

\epsilon = \frac{\Delta L}{L}

L = \frac{\Delta L}{\epsilon} = \frac{1.35}{0.00075} = 1800 mm or 1.8m

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an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror sh
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Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

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Answer:

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Explanation:

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