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BabaBlast [244]
3 years ago
11

Select all the items on the following list that are ions.

Chemistry
2 answers:
Ratling [72]3 years ago
7 0

anything with plus or minus on them are ions
so that is 4 of them
po4-3
hco3-
al+3
hg2+2
Ad libitum [116K]3 years ago
3 0

Explanation:

Ions are the species that contain either a positive or negative charge.

For example, PO^{3-}_{4}, Al^{3+}, Hg^{2+}_{2}, HCO^{3-} are all ions.

Whereas when two or more different atoms are bonded together then the product formed is known as a compound.

For example, Na_{2}CO_{3} is a compound.

On the other hand, species that do not contain any charge are known as neutral species.

For example, fe, Zn, Cu are all neutral atoms.

Thus, we can conclude that items which represent the ions are as follows.

PO^{3-}_{4}, HCO^{3-}, Al^{3+}, and Hg^{2+}_{2}

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Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?
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The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

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An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
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In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

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An acid
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Determine the type of reaction for the following equation:<br> C2H6 + O2à H2O + CO2
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Answer:

The type of reaction for the following equation is combustion equation.

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Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

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The reaction given to us:

C_2H_6 + \frac{7}{2}O_2\rightarrow 3H_2O + 2CO_2

When 1 mole of ethane reacts with 7/2 moles of oxygen gas it gives 3 moles of water and 2 moles of carbon dioxide gas.

The type of reaction for the following equation is combustion equation.

4 0
3 years ago
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