All categories

4 years ago

Select all the items on the following list that are ions.

Chemistry

2 answers:

Ratling [72]4 years ago

7 0

anything with plus or minus on them are ions
so that is 4 of them
po4-3
hco3-
al+3
hg2+2

Ad libitum [116K]4 years ago

3 0

Explanation:

Ions are the species that contain either a positive or negative charge.

For example, $PO^{3-}_{4}$ , $Al^{3+}$ , $Hg^{2+}_{2}$ , $HCO^{3-}$ are all ions.

Whereas when two or more different atoms are bonded together then the product formed is known as a compound.

For example, $Na_{2}CO_{3}$ is a compound.

On the other hand, species that do not contain any charge are known as neutral species.

For example, fe, Zn, Cu are all neutral atoms.

Thus, we can conclude that items which represent the ions are as follows.

$PO^{3-}_{4}$ , $HCO^{3-}$ , $Al^{3+}$ , and $Hg^{2+}_{2}$

You might be interested in

Find the molality of a solution of 58.5 g NaCl dissolved in 0.556 kg of water

Anit [1.1K]

Answer:lmk

Explanation:

3 0

3 years ago

3h2so4 2b(oh)3 - b2(so4)3 6h2o what is the mole ratio between water and sulfuric acid?

Nutka1998 [239]

Since there is an equal number of each element in the reactants and products of 3H2SO4 + 2B(OH)3 = B2(SO4)3 + 6H2O, the equation is balanced.

<h3>What is Sulfuric acid?</h3>

Sulfuric acid (H2S04) is a corrosive substance, that destroys the skin, eyes, teeth, and lungs. Severe vulnerability can result in death. Workers may be harmed from disclosure to sulfuric acid. The level of exposure depends on

The sulfuric acid bleaching can substitute the presently assumed oxygen and chlorine stages if the additives are allowed. This bleaching process was also practical for oxygen-bleached hardwood kraft pulp, but it was less compelling for softwood kraft pulp and oxygen-bleached softwood kraft pulp.

Disbanding sulfuric acid in water is an exothermic procedure. When sulfuric acid is mixed with ice this exothermic procedure causes the temperature to rise at first, but as more of the ice dissolves, the temperature falls.

To learn more about Sulfuric acid, refer to:

brainly.com/question/10220770

#SPJ4

8 0

1 year ago

The freezing temperature of water is zero on both the "K" and "C" scales. True False

Vera_Pavlovna [14]

False, 0 degrees on the K scale is absolute zero.

8 0

3 years ago

Determine whether the graph is that of a function by using the vertical-line test. If it is, use the graph to find (a) its domai

Ilia_Sergeevich [38]

Answer:

Following are the solution to this question:

Explanation:

If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise. They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:

In point a:

$\to Domain= [-\pi ,\pi ]\\\\\to Range = [-1,1]$

In point b:

Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.

$\to y-intercept = 1\\\\\to x-intercept = \frac{\pi}{2} ,- \frac{\pi}{2} \\\\$

In point C:

Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.

3 0

3 years ago

Please Help!!

vekshin1

Answer:

1. By Pressure factor: if we double the pressure volume become half of its original

2. 2.14 L

3. 2.15 L

Explanation:

part 1

Data Given:

volume of container change

temperature of remain constant

The pressure doubles

Solution:

This problem can be explained by Boyle's Law that at constant temperature pressure and volume has an inverse relation with each other.

So the volume change due to change in Pressure.

P1V1 = P2V2

if we consider conditions at STP, as follows

initial volume V1 = 22.42 L

and

initial pressure P1 = 1 atm

if the pressure doubles then

final pressure P2 = 2 atm

Put values in Boyle's law equation

(1 atm) (22.42L) = (2 atm) (V2)

Rearrange the above equation to find V2

V2 = (1 atm) (22.42L) / 2 atm

V2 = 11.12 L

So it is clear from calculation if we double the pressure volume become half of its original. So its the pressure due to volume become effected and decrease by its increase.

_____________

Part 2

Data Given:

Initial temperature T1= 250 K

final Temperature T2= 350 K

initial volume V1 = ?

final volume V2 = 3.0 L

Solution:

This problem will be solved by Charles' Law equation at constant pressure

V1 / T1 = V2 / T2 . . . . . . . . (1)

put values in above equation

V1 / 250 K = 3.0 L / 350 K

Rearrange the above equation to calculate V1

V1 = (3.0 L / 350 K) x 250 K

V1 = (0.0086 L . K) x 250 K

V1 = 2.14 L

So the initial volume = 2.14 L

_________________

part 3

Data Given:

Initial temperature T1= 20 ºC

Convert Temperature from ºC to Kelvin

T = ºC + 273

T = 20 + 273 = 293 K

final Temperature T2= -5.00 ºC

Convert Temperature from ºC to Kelvin

T = ºC + 273

T = - 5.00 + 273 = 268 K

initial volume V1 = 2.35 L

final volume V2 = ?

Solution:

This problem will be solved by Charles' Law equation at constant pressure

V1 / T1 = V2 / T2 . . . . . . . . (1)

put values in above equation

2.35 L / 293 K = V2 / 268 K

Rearrange the above equation to calculate V1

V2 = (2.35 L / 293 K) x 268 K

V2 = (0.008 L . K) x 268 K

V2 = 2.15 L

So the volume at -5.00ºC = 2.15 L

6 0

4 years ago