Answer 1) In the given reaction of sulfuric acid
On addition of nitrogen monoxide gas the reaction rate increases and more amount of product is formed.
So, it is clear that NO is the catalyst in this reaction.
Answer 2) This can be proven that NO is catalyst because it increases the rate of the reaction, but it is not consumed during the reaction, and it also gets regenerated at the end of reaction.
Hence, nitrogen mono oxide is considered as the catalyst in the given reaction.
Answer 3) It increases the rate of reaction by decreasing the activation energy of the reaction. Also it can be clearly seen in this reaction the NO is reacting with oxygen to lower the energy of activation. So, it is providing an alternative pathway for proceeding the reaction. This all confirms the assumptions of NO being the catalyst.
Answer:
A. They must be kept separate from moisture and oxygen
Explanation:
Alkali metals refers to a group of chemical elements in the periodic table. It is the common name given to Group 1 elements (excluding hydrogen). They are generally metallic in nature with physical properties like shining lustre, silvery in appearance etc. Alkali metals include lithium, Pottasium, Sodium, Rubidium etc.
One important chemical property of alkali metals is their high reactivity i.e. they tend to react quickly with other substances. For example, alkali metals react vigorously with water to form hydroxides. They also react with oxygen to form oxides. Due to this highly reactive properties, they are kept or stored away from moisture (water) and oxygen (present in air).
Answer:
The answer to your question is V2 = 4.97 l
Explanation:
Data
Volume 1 = V1 = 4.40 L Volume 2 =
Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C
Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg
Process
1.- Convert temperature to °K
T1 = 19 + 273 = 292°K
T2 = 37 + 273 = 310°K
2.- Use the combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (783 x 4.40 x 310) / (292 x 735)
-Simplification
V2 = 1068012 / 214620
-Result
V2 = 4.97 l
I think its c because solid,liquid nor plasma really fits to the description and i don't really know the last one so the best option is probably C.
Yes it is available. It will continue catalyzing the reactions until it becomes completely consumed. That's how enzymes work. They work and are eventually consumed in the process completely without altering the reaction in any way other than speeding it up.
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