<h3>
Answer:</h3>
H+ contains 1 proton, 0 neutrons, 0 electrons.
<h3>
Explanation:</h3>
- An atom is the smallest particle of an element that can take part in a chemical reaction.
- Atoms are made of sub-atomic particles neutrons and protons found in the nucleus and electrons found in the energy levels.
- A hydrogen atom contains 1 proton and 0 neutrons in the nucleus and 1 electron in the energy levels.
- A hydrogen atom loses an electron to form an ion with 1 proton, 0 neutron and 0 electron.
Answer:
The voltage or potential difference
Explanation:
What makes current flow in a circuit is the voltage or the potential difference.
This force is supplied by the battery or the mains electrical circuit.
- Every circuit requires the voltage to drive current through
- When a circuit is complete, the battery is able to overcome any resistance by the generating enough voltage which is the force to drive the current through.
You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45
Answer:
The exceptions to the periodic trends in ionization energy are the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.
Explanation:
Taking a close look at the figure of first ionization energies, it clearly shows that the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.
This is as a result of Hund's rule and electron configuration. For example, the first ionization potential electron of beryllium is obtained from a 2s orbital while that of boron comes from a 2p electron. However, for oxygen and nitrogen, their electrons are obtained from 2p orbitals. While spin is uniform for all 2p electrons of nitrogen, it is different for oxygen.
