Answer:
NH3(aq)
Explanation:
Gold III hydroxide is an inorganic compound also known as auric acid. It can be dehydrated at about 140°C to yield gold III oxide. Gold III hydroxide is found to form precipitates in alkaline solutions hence it is not soluble in calcium hydroxide.
However, gold III hydroxide forms an inorganic complex with ammonia which makes the insoluble gold III hydroxide to dissolve in ammonia solution. The equation of this complex formation is shown below;
Au(OH)3(s) + 4 NH3(aq) -------> [Au(NH3)4]^3+(aq) + 3OH^-(aq)
Hence the formation of a tetra amine complex of gold III will lead to the dissolution of gold III hydroxide solid in aqueous ammonia.
Solution :
In the field of chemistry, the cationic polymerization is a kind of the chain growth polymerization where the cation initiator transfers the charge to the monomer and makes it more reactive. This kind of polymerization reaction is very sensitive to the temperature. With increase in temperature, the molecular weight as well as the reaction rate decreases rapidly.
Thus in the cationic polymerization of the 3,3-dimethyl-1-butene, the carbonation intermediate is formed and it rearranges itself. The attack o the 2nd alkene ca take place both the carbonations, so that random copolymer is formed.
Answer:
The possible values of l are 2 and 3
Explanation:
Each electrons have four quantum numbers:
- n: the principal quantum number, which value matches with the energy level of the electron.
- l: the secondary quantum number, which value can be from 0 to n-1
- m: the magnetic number, which value can be from -l to l
- sp: the spin number which value can be -1/2 or +1/2
In this case, n=4 so the values of l are:
l=0, 1, 2, 3
Now, if:
- l=0 the value of m is m=0
- l=1 the values of m are m= -1, 0, 1
- l=2 the values of m are m= -2, -1, 0, 1, 2
- l=3 the values of m are m= -3, -2, -1, 0, 1, 2, 3
Being all that said, l can be either equal to 2 or 3
The answer is 4.
Gases have low densities, because of the increased space between hight-energy particles.
