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4 years ago

Forces of attraction limit the motion of the particles most in ________.

Physics

1 answer:

Ahat [919]4 years ago

8 0

Answer:

D.) both b and c

Explanation:

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A cylindrical metal bar of diameter 14cm and length 484 cm is to be melted to make a metalic cube.if one side of the box is 220m

asambeis [7]

The number of boxes were produced willl be 7.57.n stands for the no of boxes.

<h3>What is volume?</h3>

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The volume of the cylindrical metal bar;

V₁=πr²h

V₁=3.4 × 7² × 484 cm

V₁=80,634.4 cm³

The one side of the box is,220mm(22 cm)

V₂ = a³

V₂ = (22)³

V₂ = 10,648 cm³

The no of boxes is found as;

n = V₁/V₂

n=80,634.4 cm³/10,648 cm³

n=7.57

Hence, the number of boxes were produced willl be 7.57

To learn more about the volume, refer to brainly.com/question/1578538

#SPJ2

5 0

2 years ago

The human body is an organism made up of cells, tissues, organs, and organ system. Here are examples of three types of muscle ti

REY [17]

I would think that would be C.

8 0

3 years ago

Một chất điểm đang chuyển động với vận tốc 10(m/s) thì tăng tốc sau khi đi được 20(s) thì vật có vận tốc 20 (m/S)

Makovka662 [10]

Answer:8huhyuj

uhuhjuhnjknjnm

Explanation:

nuhyuihtyi8uij

5 0

3 years ago

Uncle Harry weighs 750 N. What is his mass in kg?

Elenna [48]

Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

8 0

3 years ago

Read 2 more answers

An insulated Thermos contains 140 cm3 of hot coffee at 85.0°C. You put in a 15.0 g ice cube at its melting point to cool the cof

Pavel [41]

Answer:

$T = 69^o C$

Explanation:

Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes

So here we have

$Q_{ice} = Q_{coffee}$

now since ice cubes are added into coffee when it is at melting temperature

So here we can say that final temperature of coffee is T degree C

Now we have

$m_1L + m_1c_1\Delta T_1 = m_2c_2\Delta T_2$

here we have

$m_1 = 15 gram$

L = 333 kJ/kg = 333 J/g[/tex]

$c_1 = c_2 = 4186 J/kg C = 4.186 J/g C$

$\Delta T_1 = T - 0$

$\Delta T_2 = 85 - T$

now we have

$15(333) + 15(4.186)(T - 0) = 140(4.186)(85 - T)$

$4995 + 62.79T = 49813.4 - 586.04T$

$648.83 T = 44818.4$

$T = 69^o C$

6 0

3 years ago