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Ivanshal [37]
3 years ago
6

The initial volume reading in a graduated cylinder is 30 mL. The mass of an irregular shape of an unknown metal piece is 55.3 g.

The final volume reading in the graduated cylinder is 37 mL. The density of this unknown metal is _____.
Physics
1 answer:
Vadim26 [7]3 years ago
6 0

Answer:

7.9\frac{gr}{cm^3}

Explanation:

When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.

So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7cm^3).

Density is \frac{mass}{volume}.

So the density of that piece of metal is \frac{55.3g}{7cm^3}

Which leaves us with a final density of 7.9\frac{gr}{cm^3}

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The specific heat of water is 4.19 x 103 J/kg°C. How much energy will it take to raise the temperature of 0.5 kg of water by 2 d
fredd [130]
Energy required = mass x specific heat x temperature difference
= 0.5 x 4.19x10^3 x 2
= 4190J
5 0
3 years ago
A monster truck enters a freeway with a speed of 0 m/s and accelerates at a rate of 25 m/s2 in 5 seconds. How far does the car t
Furkat [3]

Answer:

312.5

Explanation:

we know that

s= ut + 1/2 at^2

= 0*5+1/2*25*5^2

= 0+ 625/2

=312.5

plz mark as brainalist

5 0
3 years ago
The blank approach emphasizes the scientific study of observable actions and/or responses and their environmental determinants
lakkis [162]

Answer:

"behavioral" is the right answer.

Explanation:

  • The behavioral approach would be founded on the principle of generating information thru all the extrapolation as well as the believing which our ecosystem might be what tends to create us to differ greatly as well as experience severe sickness.
  • Throughout several other phrases, it is indeed an analysis of the relationship among both our thoughts as well as our attitudes or actions.
8 0
3 years ago
A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh =  0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

6 0
3 years ago
A bathysphere used for deep-sea exploration has a radius of 1.50 m and a mass of 1.19 104 kg. In order to dive, this submarine t
Hitman42 [59]

Answer:

m = 2,776.95 kg

Explanation:

given,

radius = 1.5 m

mass = 1.19 x 10⁴ Kg

constant speed, v = 1.4 m/s

Resistive force = 1105 N

density of sea water = 1.03 x 10³ kg/m³

Volume of vessel,

v=\dfrac{4}{3}\pi r^3

v=\dfrac{4}{3}\pi\times 1.5^3

v = 14.14 m³

Upthrust,

U = ρ g V

U = 1030 x 9.8 x 14.14

U  = 142729.16 N  

Since the vessel is moving at a constant speed, the resultant force on it should equal zero.

downward acting forces = upward acting forces

Mg = U + resistive force

M x 9.8 = (142729.16+1105)

M=14676.95 Kg

Mass of water,

m = M - mass of vessel  

m = 14676.95 Kg- 11,900 kg  

m = 2,776.95 kg

5 0
3 years ago
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