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USPshnik [31]
3 years ago
9

Which equation is used to determine the density of a substance

Physics
1 answer:
9966 [12]3 years ago
8 0

Density = (mass)/(volume)

IF 'D' means density, 'M' means mass, and 'V' means volume, then choice-A is the equation to use.

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The sidereal period of the moon around the Earth is 27.3 days. Suppose a satellite were placed in Earth orbit, halfway between E
icang [17]

Answer: 9.7 days

Explanation:

Applying Kepler's 3rd law, we can write the following proportion:

(Tm)² / (dem)³ = (Tsat)² / (dem/2)³

(As the satellite is placed in an orbit halfway between Erth's center and the moon's orbit).

Simplifyng common terms, and solving for Tsat, we have:

Tsat = √((27.3)²/8) = 9.7 days

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3 years ago
This chart shows characteristics of three different waves all with the same wavelength of 10 m but moving at different frequenci
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Answer:

the answer is B

Explanation:

wave x has the highest hertz making it the answer

6 0
3 years ago
Example of the center of the gravity<br>​
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The example of the center of the gravity is the middle of a seesaw

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5 0
3 years ago
Two students are on a balcony 19.1 m above the street. One student throws a ball, b1, vertically downward at 13.9 m/s. At the sa
tester [92]

Answer:

Part a)

t = 2.83 s

Part b)

Ball thrown downwards =v_f = 23.8 m/s

Ball thrown upwards =v_f = 23.8 m/s

Part c)

d = 22.24 m

Explanation:

Part a)

Since both the balls are projected with same speed in opposite directions

So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection

Afterwards the motion will be same as the first ball which is projected downwards

so here the time difference is given as

\Delta y = 0 = v_y t + \frac{1}{2}at^2

0 = 13.9 t - \frac{1}{2}(9.81) t^2

t = 2.83 s

Part b)

Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls

so it is given as

v_f^2 - v_i^2 = 2 a \Delta y

v_f^2 - (13.9)^2 = (2)(-9.81)(-19.1)

v_f^2 = 567.9

v_f = 23.8 m/s

Part c)

Relative speed of two balls is given as

v_{12} = v_1 - v_2

v_{12} = (13.9) - (-13.9) = 27.8 m/s

now the distance between two balls in 0.8 s is given as

d = v_{12} t

d = 27.8 \times 0.8

d = 22.24 m

7 0
4 years ago
How do you comprehend the fourth dimension?
sergij07 [2.7K]
The fourth dimension is technically time. the fourth dimension that you are talking about is actually impossible to comprehend.
6 0
3 years ago
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