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Artemon [7]
3 years ago
13

Think about plotting the distances as points on a number line where 0 represents the position of the Sun. Based on your scaling

work in question 1, what is one challenge of modeling the distances of inner and outer planets using the same scale? You can create a rough sketch to guide you.
Physics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

The distance between an inner planet and the Sun is small compared with the distance between an outer planet and the Sun. If inner and outer planets are drawn to the same scale on a number line, the inner planets will bunch near zero (the Sun's position) and might appear on top of one another.

Explanation:

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A car is accelerating at a rate of 35 m/s2 and has a resulting velocity increase from 17 m/s to 26 m/s. How long did it take to
harina [27]

Answer:The answer is (60 mph - 0 mph) / 8s = (26.8224 m/s - 0 m/s) / 8s = 3.3528 m/s 2 (meters per second squared) average acceleration. That would be 27,000 miles per hour squared.

Explanation:

6 0
3 years ago
An object is located 50.0 cm from a concave mirror. The magnitude of the mirror focal length is 25.0 cm. What is the image dista
ioda

Answer:

Correct answer: C. 50 cm

Explanation:

Given data:

The distance of the object from the top of the concave mirror o = 50.0 cm

The magnitude of the concave mirror focal length 25.0 cm.

Required : Image distance d = ?

If we know the focal length we can calculate the center of the curve of the mirror

r = 2 · f = 2 · 25 = 50 cm

If we know the theory of spherical mirrors and the construction of figures then we know that when an object is placed in the center of the curve, there is also a image in the center of the curve that is inverted, real and the same size as the object.

We conclude that the image distance is 50 cm.

We will now prove this using the formula:

1/f = 1/o + 1/d => 1/d = 1/f - 1/o = 1/25 - 1/50 = 2/50 - 1/50 = 1/50

1/d = 1/50 => d = 50 cm

God is with you!!!

6 0
3 years ago
Read 2 more answers
A speeding car collides with an unlucky bug flying across the road. Which explains why the impact doesn’t equally damage the car
velikii [3]
The bug was a lot smaller than the car, that's for sure. The car is bigger and sturdier, while the bug is smaller and frail. The bug is so frail, that rather that putting a dent in the car, it splatters all over the car. The bug is very damaged (obviously), while the car just needs a good wash.
8 0
3 years ago
A rock moving a 15m/s accelerates at 9.8m/s for 12s. what is the final velocity of the rock?
ryzh [129]
1.25 is the answer to tht if im right but could be wrong
4 0
3 years ago
How would you classify an EM wave with a frequency of 10^7 Hz?
tiny-mole [99]

Answer:

I think it is television and radio wave

5 0
3 years ago
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