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Artemon [7]
3 years ago
13

Think about plotting the distances as points on a number line where 0 represents the position of the Sun. Based on your scaling

work in question 1, what is one challenge of modeling the distances of inner and outer planets using the same scale? You can create a rough sketch to guide you.
Physics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

The distance between an inner planet and the Sun is small compared with the distance between an outer planet and the Sun. If inner and outer planets are drawn to the same scale on a number line, the inner planets will bunch near zero (the Sun's position) and might appear on top of one another.

Explanation:

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A racecar driver circles a racetrack with a constant speed of 110 km/hr. Which BEST describes the speed and velocity of the car?
tangare [24]
The answer is B, The speed is constant and the velocity is changing.
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3 years ago
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What is the most potentially destructive way to deal with stress while at college? a. texting friends back home b. watching TV c
diamong [38]

Answer:

Option (C)

Explanation:

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So, recreational drugs are one of the most potentially destructive ways to handle stress when a student is in college.

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7 0
3 years ago
Slow moving vehicles must display ___________ emblem at the rear to warn of their low speed.
KIM [24]
<span>Slow moving vehicles must display reflective emblem at the rear to warn of their low speed.

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6 0
3 years ago
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A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x
SIZIF [17.4K]

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

4 0
2 years ago
Round off to the nearest one (units place):
Elina [12.6K]

Answer:

a

Explanation:

7 0
3 years ago
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