Answer:
weight
Explanation:
The weight of an object is the force of gravity on the object and may be defined as the mass times the acceleration of gravity, w = mg. Since the weight is a force, its SI unit is the newton. Density is mass/volume.
The answer is real and smaller than the object. The image point of the top of the object is the point where the two refracted rays intersect. Tracing the entire image having the same distance from the mirror as the image of the top of the object and with the bottom on the principal axis. Hence, a real inverted image will be formed for an object outside the focal point.
Answer:
Part a)
![\phi = -4.76 \times 10^{-3} Nm^2/C](https://tex.z-dn.net/?f=%5Cphi%20%3D%20-4.76%20%5Ctimes%2010%5E%7B-3%7D%20Nm%5E2%2FC)
Part b)
![\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C](https://tex.z-dn.net/?f=%5Cphi_%7Bcurved%7D%20%3D%204.76%20%5Ctimes%2010%5E%7B-3%7D%20Nm%5E2%2FC)
Explanation:
Part a)
Electric flux entering into the base
so it is given as
![\phi = E.A](https://tex.z-dn.net/?f=%5Cphi%20%3D%20E.A)
![\phi = - EA](https://tex.z-dn.net/?f=%5Cphi%20%3D%20-%20EA)
![\phi = -(1.64)(\pi r^2)](https://tex.z-dn.net/?f=%5Cphi%20%3D%20-%281.64%29%28%5Cpi%20r%5E2%29)
![\phi = -(1.64)(\pi\times 0.0304^2)](https://tex.z-dn.net/?f=%5Cphi%20%3D%20-%281.64%29%28%5Cpi%5Ctimes%200.0304%5E2%29)
![\phi = -4.76 \times 10^{-3} Nm^2/C](https://tex.z-dn.net/?f=%5Cphi%20%3D%20-4.76%20%5Ctimes%2010%5E%7B-3%7D%20Nm%5E2%2FC)
Part b)
Now since we know that there is no enclosed charge in the hemisphere
so net flux must be zero
![\phi_{curved} + \phi_{flat} = 0](https://tex.z-dn.net/?f=%5Cphi_%7Bcurved%7D%20%2B%20%5Cphi_%7Bflat%7D%20%3D%200)
![\phi_{curved} - 4.76 \times 10^{-3} = 0](https://tex.z-dn.net/?f=%5Cphi_%7Bcurved%7D%20-%204.76%20%5Ctimes%2010%5E%7B-3%7D%20%3D%200)
![\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C](https://tex.z-dn.net/?f=%5Cphi_%7Bcurved%7D%20%3D%204.76%20%5Ctimes%2010%5E%7B-3%7D%20Nm%5E2%2FC)
<em> </em><em> </em><em>62.125</em>
<em>=</em><em> </em><em>62.12</em>
<em>THANK</em><em> </em><em>you</em><em> </em>
Answer:
2.4 m/s
Explanation:
Given:
Velocity of the object moving north = 2.1 m/s
Velocity of the river moving eastward = 1.2 m/s
The resultant velocity is the vector sum of the velocities of object and river.
Since the directions of velocity of object and river are perpendicular to each other, the magnitude of the resultant velocity is obtained using Pythagoras Theorem.
The velocities are the legs of the right angled triangle and the resultant velocity is the hypotenuse.
The magnitude of the resultant velocity (R) is given as:
![R^2=2.1^2+1.2^2\\\\R^2=4.41+1.44\\\\R=\sqrt{5.85}\\\\R=2.4\ m/s](https://tex.z-dn.net/?f=R%5E2%3D2.1%5E2%2B1.2%5E2%5C%5C%5C%5CR%5E2%3D4.41%2B1.44%5C%5C%5C%5CR%3D%5Csqrt%7B5.85%7D%5C%5C%5C%5CR%3D2.4%5C%20m%2Fs)
Therefore, the resultant velocity has a magnitude of 2.4 m/s.