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3 years ago

2# Find the missing variable (s). Round to the nearest tenth.

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer:

15 cos(33°) m

Step-by-step explanation

Presumably m stands for meters.

If RS were 1, x would be cos(33°)

Multiply sides of triangle by 15 m

When calculating cos(33°) first make sure cos(90°) comes out zero, not -0.448...

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A text font fits 12 characters per inch.Using the same font how many characters can be expected per yard of text?

Ludmilka [50]

1 foot = 12 inches

1 yard = 3 feet = 36 inches

36*12 = 432 characters

3 0

3 years ago

Which is greater 45 hundredths or 6 tenths

MA_775_DIABLO [31]

45 hundredths is greayer than 6 tenth because 45 is in the hundredths spot and 6 is in the tenth spot

4 0

4 years ago

Show all work to identify the asymptotes and zero of the function f(x) = 6x / x^2 - 36

eduard

Answer:

Zero of the function f(x) is at x = 0

Vertical Asymptotes at x = ±6

Horizontal Asymptotes at y = 0

Step-by-step explanation:

<h3>Vertical Asymptotes </h3>

For a given function f(x):

Vertical Asymptotes are obtained at those values of x, where the function f(x) tends to infinity, I.e.,

When x approaches some constant value but the curve moves towards infinity.

If f(x) is a fraction, it'll tend to infinity when it's denominator becomes zero.

Vertical Asymptotes of the given function can be obtained by walking thru the following steps:

Step I

(Factorise the numerator and denominator)

$\mathsf{ f(x) = \frac{6x}{ {x}^{2} - 36 } }$

x² - 36 can be factorised into (x + 6)(x - 6)

and, ofcourse, we can write 6x as 6(x - 0)

$\mathsf{ f(x) = \frac{6(x - 0)}{ (x + 6)(x - 6) } }$

Step II

(Reduce the fraction to its simplest form by canceling out the common factors)

There aren't any common factors in the numerator and denominator in this case.

Step III

(Look for the values of x which cause the denominator to be zero)

If we put x = 6

denominator becomes 0

Also,

If we substitute x with -6

denominator becomes 0.

The two values of x indicate the two Vertical Asymptotes of the function f(x).

Therefore,

Vertical Asymptotes of the given function f(x) are:

$\boxed{ \mathsf{x = \pm6}}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 /><h3>Horizontal Asymptotes:</h3>

Horizontal Asymptotes are obtained When x tends to infinity and y approaches some constant value.

I'll be using the concept of limits for this.

$\mathsf{y = \frac{6x}{ {x}^{2} - 36 } }$

dividing and multiplying by x² (Yep! so if x becomes infinity 1/ x and 1/ x² all such terms become 0, 'cause 1/ ∞ is 0)

$\implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6x}{ {x}^{2} } }{ \frac{ {x}^{2} - 36 }{ {x}^{2} } } ) }$

$\implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6}{ x } }{ 1- \frac{36 }{ {x}^{2} } } ) }$

Substitute x with ∞, you get zero/ 1

$\implies \boxed{\mathsf{y = 0}}$

So, the horizontal Asymptote of the function is y = 0, that is the x axis

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Zeroes of a function:</h3>

The values of x that reduces f(x) to zero are called the zeroes of f(x).

Here, only x = 0 acts as the zero of the function.

[NOTE:

For finding Vertical Asymptotes,Equate the denominator to 0. And
For finding Zeroes, Equate the numerator to 0]

__________________

[That's what it's graph looks like. ]

3 0

3 years ago

!! will give brainliest

drek231 [11]

Answer:

zoom in

this is the right answer

don't forget to mark me as brainliest

4 0

3 years ago

In the upcoming election for governor, the most recent poll, based on 900 respondents, predicts that the incumbent will be reele

Paul [167]

Answer:

.0166

Step-by-step explanation:

Central Limit Theorem for proportions:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $\sigma_{p} = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$n = 900, p = 0.55$

What is σρˆ?

The standard deviation of the sample proportion, which is:

$\sigma_{p} = \sqrt{\frac{0.55*0.45}{900}} = 0.0166$

4 0

3 years ago