Answer:
The sum of first 30 terms of the arithmetic progression is <u>2160.</u>
Explanation:
For an arithmetic progression, the sum of first
terms with first term as
and common difference
is given as:

Now, it is given that:

Now, plug in these values and frame two equations in 


Now, we solve equations (1) and (2) for
. Subtract equation (1) from equation (2). This gives,

Now, plug in the value of
in equation (1) and solve for
.

Plug in the values of
in the sum formula to find the sum of first 30 terms.
Now, the sum of first 30 terms is given as:

Therefore, the sum of first 30 terms of the arithmetic progression is 2160.
12 moles H2O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
Answer:
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Explanation:
我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈
(2) Adding more O2(g) would shift the equilibrium to the right because a higher concentration of oxygen is offered than its initial position, therefore more products have to be yielded to maintain equilibrium.
Answer:
C. Chain Reaction
Explanation:
You get different elements from just one by a single reaction.