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Genrish500 [490]
3 years ago
9

A man drove his car through the Nevada desert one day when the temperature was over 100°F. When he started the trip, the gas sta

tion attendant found the tire to be 32 lb/in2. When he filled up with gas after crossing the desert, an attendant found the tire pressure to be 38 lb/in2. What is the best explanation for the increase in tire pressure?
The road wear on the tire caused a decrease in volume and, therefore, an increase in tire pressure.
The temperature in the tire increased, causing an increased tire pressure.
The hot temperature caused the springs to expand, which allowed more weight to ride on the tires, thus causing more pressure inside.
The measurements of the pressure were inaccurate. The added weight of the gas caused the extra pressure in the tires.
Chemistry
1 answer:
Slav-nsk [51]3 years ago
7 0
<span>The temperature in the tire increased, causing an increased tire pressure. :D</span>
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How many significant digits does the number 700 have?
OLga [1]

Answer: 700 has one significant figure which is 7.

Explanation: These are some rules for significant figures

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•Leading zeros are not significant: There are two significant figures in 0.56.

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•Trailing zeros in a whole number with the decimal shown are significant: This makes "700." three significant figures.

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a. neutral

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Time zones were adopted to fix what problem
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3 years ago
if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
3 years ago
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