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LuckyWell [14K]
2 years ago
11

How are primary and secondary pollutants alike?

Chemistry
1 answer:
Zarrin [17]2 years ago
5 0

Answer:

Primary pollutants are emitted from natural or anthropogenic sources directly into the atmosphere, while secondary pollutants result from the chemical reactions or the physical interactions between the primary pollutants themselves or between the primary pollutants and other atmospheric components.

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In the croquignole method of wrapping, the hair is wound from the _____ in overlapping concentric layers. a. longest to the shor
True [87]

Answer: d. ends to the scalp

In the croquignole method of wrapping the hair is wrapped and wound from the ends (tip) to the scalp in the overlapping layers. This method is used to produce a physical change in the hair, that is providing a waving or curling pattern to the hair. The curls of hair are usually tighter at the ends and gets larger nearer the scalp.

6 0
3 years ago
The OH-ion concentration of a blood sample is
Keith_Richards [23]

Answer:

She okeyy

Explanation:

Example 740 are the think free ofıce pH of the blood 740 blood sample iş takipte kal ❣️

4 0
3 years ago
Having done the experiment, explain briefly how the mass of zinc not equal the mass of lead gained (hint: the periodic table)
masya89 [10]

Answer:

Due to the difference in the relative atomic masses and therefore, the molecular masses of Zn and Pb, one mole of Zn is about 3.2 times lighter than one mole of Pb

Explanation:

From the periodic table, we have;

The atomic number of zinc, Zn = 30

The atomic mass of zinc, Zn = 65.38 amu

The molar mass of zinc, Zn = 65.38 g/mol

The atomic number of lead, Pb = 82

The atomic mass of lead, Pb = 207.2 amu

The molar mass of lead, Pb = 207.2 g/mol

Therefore, whereby equal number of moles of Zn is lost and Pb is gained, we have;

Mass of 1 mole of Zn = 65.38 grams

Therefore, 1 gram of Zn = 1/65.38 moles = 0.0153 moles

0.12 grams of Zn = 0.12×0.0153 = 0.00184 moles of Zn

Given that equal number of moles of Zn and Pb are involved in the reaction, the number of moles of Pb gained = 0.00184 moles

The mass of Pb gained = Number of moles of Pb gained × Molar mass of Pb

The mass of Pb gained = 0.00184 × 207.2 = 0.38 g ≈ 0.4 g.

Amount of Pb gained = 0.43 g ≈ 0.4 g

4 0
3 years ago
if a vacuum pump reduces the pressure of a gas to 1.0x10^-6 atm, what is the pressure expressed in millimeters of mercury
lana [24]
1,322.751322751323 mmHg
5 0
3 years ago
A welding torch requires 602.1 L of ethylene gas at 2.77 atm. What will be the pressure of the gas if ethylene is supplied by a
Katarina [22]
PV=PV
(602.1 L)(2.77atm) = (110.6 L) (X atm)
1667.817=110.6X
15.07971971 atm = X
Rounds to 15.1 (sig figs so much fun)
8 0
2 years ago
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