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leva [86]
2 years ago
14

+30 points

Chemistry
1 answer:
solong [7]2 years ago
3 0

Answer:

where a cold air mass is replacing a warmer air mass. ... The air behind a cold front is noticeably colder and drier than the air ahead of it. When a cold front passes through, temperatures can drop more than 15 degrees within the first hour.

Explanation:

The effects from a cold front can last from hours to days. The air behind the front is cooler than the air it is replacing and the warm air is forced to rise, so it cools. As the cooler air cannot hold as much moisture as warm air, clouds form and rain occurs.

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___________ is the scale used to describe how acidic or basic a solution is. This affects the enzymes within living systems.
nydimaria [60]

Answer:

pH scale

Explanation:

pH scale -

In the field of chemistry , the accurate and exact value of acidity or basicity in a particular solution is calculated with the help of a pH scale .

The scale has reading ranging from 1 to 14 ,

where ,

  • If the pH value less than 7 indicates the solution to be acidic in nature ,
  • If the pH value is exactly equal to 7 , the solution is neutral in nature ,

and ,

  • If the pH value more than 7 indicates the solution to be basic in nature ,

Hence , from the given statement of the question ,

The correct answer is pH scale .

3 0
2 years ago
the element weighed 3.555 grams when it was burned in oxygen an oxide compound was produced. the product mass was 4.666 grams. W
vodka [1.7K]
Idk really but i hope you figure out the answer im not on that yet.
6 0
3 years ago
Help please I’ll give you brainless
Nikitich [7]

Answer:

By atomic number?

Explanation:

fingers crossed its right :/

8 0
2 years ago
Calculate the equilibrium constant for the decomposition of water 2h2o(l)  2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –
kow [346]

Answer:

2.6 ×10^-42

Explanation:

From

∆G= -RTlnK

∆G= -237.2 KJmol-1 or -237.2×10^3 Jmol-1

R= 8.314 Jmol-1K-1

T= 25°C + 273= 298K

-237.2×10^3= 8.314 × 298 × ln K

ln K= -237.2×10^3/2477.572

K = 2.6 ×10^-42

3 0
3 years ago
Explain how the cell membrane controls the movement of materials into and out of the cell ?
sukhopar [10]
It's called simple diffusion, the small molecules without charges such as oxygen and carbon dioxide can flow through a plasma membrane without assistance and without expending energy. Other substances such as proteins, glucose and charged particles called ions cannot pass through the selectively permeable membrane.
5 0
3 years ago
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