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leva [86]
2 years ago
14

+30 points

Chemistry
1 answer:
solong [7]2 years ago
3 0

Answer:

where a cold air mass is replacing a warmer air mass. ... The air behind a cold front is noticeably colder and drier than the air ahead of it. When a cold front passes through, temperatures can drop more than 15 degrees within the first hour.

Explanation:

The effects from a cold front can last from hours to days. The air behind the front is cooler than the air it is replacing and the warm air is forced to rise, so it cools. As the cooler air cannot hold as much moisture as warm air, clouds form and rain occurs.

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Calculate the number of moles of O2 gas held in a sealed 2.00 L tank at 3.50 atm and 25 ℃.
Leviafan [203]

Answer:

n=0.286mol

Explanation:

Hello,

In this case, we consider oxygen as an ideal gas, for that reason, we use yhe ideal gas equation to compute the moles based on:

PV=nRT\\\\n=\frac{PV}{RT}

Hence, at 3.50 atm and 25 °C for a volume of 2.00 L we compute the moles considering absolute temperature in Kelvins:

n=\frac{3.50atm*2.00L}{0.082\frac{atm*L}{mol*K}(25+273)K} \\\\n=0.286mol

Best regards.

6 0
3 years ago
Low tide____.
Fantom [35]

Answer:

i think the answer is A

Explanation:

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8 0
3 years ago
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yulyashka [42]

Answer:

0.256 L  

Explanation:

We should use the following formula:

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volume (1) = ?

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volume (1) = [concentration (2) × volume (2)] / concentration (1)

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