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leva [86]
3 years ago
14

+30 points

Chemistry
1 answer:
solong [7]3 years ago
3 0

Answer:

where a cold air mass is replacing a warmer air mass. ... The air behind a cold front is noticeably colder and drier than the air ahead of it. When a cold front passes through, temperatures can drop more than 15 degrees within the first hour.

Explanation:

The effects from a cold front can last from hours to days. The air behind the front is cooler than the air it is replacing and the warm air is forced to rise, so it cools. As the cooler air cannot hold as much moisture as warm air, clouds form and rain occurs.

You might be interested in
The following list contains some common radicals. Using the charges on these ions and the idea of valence, predict the formulas
lesantik [10]

Answer : The formula for the compound sodium carbonate is Na_2CO_3

The formula for the compound potassium permanganate is KMnO_4

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) CO_3^{2-}.

Here, sodium is having an oxidation state of +1 called as Na^{1+} cation and carbonate CO_3^{2-} is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, Na_2CO_3

Hence, the formula for the compound sodium carbonate is Na_2CO_3

(b) Potassium permanganate

In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) MnO_4^{1-}.

Here, potassium is having an oxidation state of +1 called as K^{1+} cation and permanganate MnO_4^{1-} is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, KMnO_4

Hence, the formula for the compound potassium permanganate is KMnO_4

3 0
3 years ago
_______A representative element in the fourth period that is an alkaline earth
MariettaO [177]

Answer:calcium

Explanation: calcium is an alkaline earth metal,group 2 period 4

4 0
3 years ago
Other questions:
vlabodo [156]

Answer:

The functional group present in Cinnamon are : Aromatic , alkene , aldehyde

The functional group present in Almonds : Aromatic , aldehyde

The functional group present in DHA  : Ketone , alcohol

Explanation:

<u>Almond :</u>

Chemical formula : C_{7}H_{6}O

It contain : A benzene ring (Aromatic) , a -CHO group (aldehyde)

<u>Cinnamon Sticks</u> :

Chemical Formula : C_{9}H_{8}O

It contain : A benzene ring (Aromatic) ,an alkene group (C=C) , a -CHO group (aldehyde)

<u> </u><u>DHA:</u>

Chemical Formula : C_{3}H_{6}O_{3}

It contain : Alcohol group (-OH) , ketone group (C=O)

8 0
3 years ago
A 6.26 g sample of a solid containing ni is dissolved in 20.0 ml water. a 5.00 ml aliquot of this solution is diluted to 100.0 m
saveliy_v [14]
Concentration of Ni in 20mL = 5.28ppm x dilution factor = 5.28 x 100/5 = 105.6 ppm = 105.6 mg/L 

molar mass of Ni = 58.6934 g
<span>Molarity of Ni = 100.40 x 10^{-3} / 58.6934 = 1.71 x 10^{-3} M = 1.71 mM. </span>
5 0
3 years ago
If 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction
RideAnS [48]

0.1 moles of chloride ions were involved  in the reaction if 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction.

Explanation:

Data given:

volume of CaCl_{2} = 25 ml 0r 0.025

molarity of the calcium chloride solution = 2M

number of chloride ions =?

Balance chemical reaction:

Ca + 2Cl_{2} ⇒Ca_{} Cl_{2}

number of moles in 25 ml is calculated as:

molarity = \frac{number of moles}{volume}

number of moles of calcium chloride  = molarity x volume

putting the values in the equation:

number of moles = 2 x 0.025

                            = 0.05 moles of calcium chloride

1 mole of  CaCl_{2}  decomposes as 1 calcium ion and 2 chloride ions

so 0.05 moles will have x moles of chloride ion

\frac{2}{1} = \frac{x}{0.05}

x= 0.1

0.1 moles of chloride ions will be involved in the reaction.

5 0
3 years ago
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