The earth is a vast, complex system powered by two sources of energy: an internal source (the decay of radioactive elements in the geosphere, which generates geothermal heat) and an external source (the solar radiation received from the Sun); the vast majority of the energy in the earth system comes from the Sun.
Explanation:
<u>Physical properties of ZBr₂</u>
The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:
- it is a hard solid usually with high melting points or a liquid with high boiling points.
- Soluble in water and insoluble in non-polar solvents.
- It can conduct electricity in aqueous solutions or in molten form.
- it will undergo a fast reaction.
<u>Z is a metal</u>
To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.
<u>Formula of the oxide</u>
ZO
Z 0
+2 -2
It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.
Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.
Learn more:
ionic compounds brainly.com/question/6071838
#learnwithBrainly
Amplitude is 5m and wavelength is 100m
!let me know if I'm wrong bc im a little rusty!
<span>Draw the Lewis structure. Bromine has 3 bonds and two lone pairs for a trigonal bipyramidal electron geometry and an sp^3d hybridization. Fluorine is peripheral it does not require hybridization, but we often consider it to be hybridized too - it has 1 bond and 3 lone pairs for sp^3 hybridization. So the sigma bonds come from an overlap of an sp^3d orbital on Br with an sp^3 orbital on F. If you don't consider the F to be hybridized the overlap would have to be to a p orbital on the F</span>
