Answer:

Step-by-step explanation:
<em>The image if the circle and triangle can be found online</em>
Given



Required
The perimeter of JKL
Since the mid-points of the tangents are A, B and C respectively.

Where


So:




Where

So:

So, the perimeter (P) is:



A^2-b^2=(a+b)(a-b)
1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
-3, -14, -27 because is subtracts by the next odd number every time
Answer:
2x^4
Step-by-step explanation: