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3 years ago

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The difference in electric potential between a thunder cloud and the ground is 1.53 108 V. Electrons move from the ground which

is at a lower potential to the cloud which is at a higher potential. Determine the change in electric potential energy of one of the electrons that move to the cloud.

1 answer:

Kryger [21]3 years ago

8 0

Answer:

=−2.451 330 152 1*10^27J

Explanation:

The electric potential=the Voltage * Charge:

E = VQ

V = 1.53x10^8 V (positive, because the cloud has a higher potential)

Q = -1.60217657 x10^19 C (the charge of an electron)

E = (1.53x10^8 V )* (-1.60217657 x10^19 C)

E=−2.451 330 152 1*10^27J

The negative sign indicates that the potential energy is decreased by the movement of the electron.

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Therefore, the magnitude of electron acceleration is $2.34 \times 10^{15}$ $\frac{m}{s^{2} }$

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