Question

use the chemical equations for the complete combustion and incomplete combustion of propane to show that matter is conserved in both situations

Answer 1

Explanation:

1) Complete combustion of propane gives carbon dioxide gas and water vapors.

The balanced chemical equation is given as:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

Number of carbon atoms on reactant side = 3

Number of hydrogen atoms on reactant side = 8

Number of oxygen atoms on reactant side = 10

Number of carbon atoms on the product side = 3

Number of hydrogen atoms on the product side = 8

Number of oxygen atoms on the product side = 10

On both the sides numbers, all elements remained the same which indicates that matter remains conserved during the course of a chemical reaction.

2) Incomplete combustion of propane gives carbon dioxide gas, carbon monoxide gas, and water vapors.

The balanced chemical equation is given as:

$2C_3H_8(g)+9O_2(g)\rightarrow 4CO_2(g)+2CO(g)+8H_2O(g)$

Number of carbon atoms on reactant side = 6

Number of hydrogen atoms on reactant side = 16

Number of oxygen atoms on reactant side = 18

Number of carbon atoms on the product side = 6

Number of hydrogen atoms on the product side = 16

Number of oxygen atoms on the product side = 18

On both the sides numbers, all elements remained the same which indicates that matter remains conserved during the course of a chemical reaction.