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Zolol [24]
3 years ago
14

In the galvanic cell Al(s) ǀ Al3+(aq, 1 M) ǀǀ Cu2+(aq, 1 M) ǀ Cu(s) which of the following changes will increase the cell potent

ial? I. Dilution of the Al3+ solution to 0.001 M II. Dilution of the Cu2+ solution to 0.001 M III. Increasing the surface area of the Al(s) electrode (A) I only (B) II only (C) III only (D) I and III only
Chemistry
2 answers:
cestrela7 [59]3 years ago
4 0

Answer:

(B) II only

Explanation:

dangina [55]3 years ago
3 0
The cathode electrode is copper. This means that the concentration of copper must be increased to increase the cell potential. This can be done by diluting the Al3+ solution. Increasing the surface area will not change the current but will increase the voltage. The answer is (D) I and III only.
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Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

6 0
3 years ago
Given the unbalanced equation: PbCl₂ + Na₂CrO₂ ---> PbCrO₂ + NaCl. When properly balanced, the sum of the balancing coefficie
Veronika [31]

Answer:

A. 2

hope this helps :)

if you need an explanation let me know!!

3 0
3 years ago
Can light move through space even though there are no molecules?
amid [387]

Answer:

This means that waves need a medium to propagate, but light waves propagate where no particles are present. ...

7 0
3 years ago
1. Butane gas (C4H10) combusts with oxygen gas (O2) to form water (H2O) and carbon dioxide (CO2). Write a balanced;’ equation fo
Mars2501 [29]

Answer:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

Explanation:

  • To balance a chemical reaction, we apply the law of conversation of mass, states that the no. of atoms in both sides of the reactants and products is the same.

So, the balanced equation of combustion of butane is:

<em>2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.</em>

  • <em>It is clear that 2.0 moles of butane is burned in 13.0 moles of oxygen to produce 8.0 moles of CO₂ and 10.0 moles of H₂O.</em>
5 0
3 years ago
Calculate the change internal energy (ΔE) for a system that is giving off 65.0 kJ of heat and is performing 855 J of work on the
ollegr [7]

Answer:  -64.1 kJ.  

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=-P\Delta V  {Work is done by the system is negative as the final volume is greater than initial volume}

w = -855 Joules = 0.855 kJ     (1kJ=1000J)

q = -65.0 kJ  {Heat released by the system is negative}

\Delta E=-65.0J-(-0.855J)=-64.1kJ

Thus the change internal energy (ΔE) for a system that is giving off 65.0 kJ of heat and is performing 855 J of work on the surroundings is -64.1 kJ.  

6 0
4 years ago
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