In the galvanic cell Al(s) ǀ Al3+(aq, 1 M) ǀǀ Cu2+(aq, 1 M) ǀ Cu(s) which of the following changes will increase the cell potent

Question

3 years ago

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In the galvanic cell Al(s) ǀ Al3+(aq, 1 M) ǀǀ Cu2+(aq, 1 M) ǀ Cu(s) which of the following changes will increase the cell potent

ial? I. Dilution of the Al3+ solution to 0.001 M II. Dilution of the Cu2+ solution to 0.001 M III. Increasing the surface area of the Al(s) electrode (A) I only (B) II only (C) III only (D) I and III only

Chemistry

2 answers:

cestrela7 [59] · Answer 1 · 2022-04-05T16:30:43+03:00

cestrela7 [59]3 years ago

4 0

Answer:

(B) II only

Explanation:

dangina [55] · Answer 2 · 2022-04-05T14:50:51+03:00

The cathode electrode is copper. This means that the concentration of copper must be increased to increase the cell potential. This can be done by diluting the Al3+ solution. Increasing the surface area will not change the current but will increase the voltage. The answer is (D) I and III only.