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Zolol [24]
3 years ago
14

In the galvanic cell Al(s) ǀ Al3+(aq, 1 M) ǀǀ Cu2+(aq, 1 M) ǀ Cu(s) which of the following changes will increase the cell potent

ial? I. Dilution of the Al3+ solution to 0.001 M II. Dilution of the Cu2+ solution to 0.001 M III. Increasing the surface area of the Al(s) electrode (A) I only (B) II only (C) III only (D) I and III only
Chemistry
2 answers:
cestrela7 [59]3 years ago
4 0

Answer:

(B) II only

Explanation:

dangina [55]3 years ago
3 0
The cathode electrode is copper. This means that the concentration of copper must be increased to increase the cell potential. This can be done by diluting the Al3+ solution. Increasing the surface area will not change the current but will increase the voltage. The answer is (D) I and III only.
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The decomposition of ammonia is: 2 NH3(g) ⇌ N2(g) + 3 H2(g). If Kp is 1.5 × 103 at 400°C, what is the partial pressure of ammoni
ValentinkaMS [17]

Answer:

"6.7\times 10^{-4} \ atm" is the right answer.

Explanation:

Given:

Partial pressure of N_2,

= 0.20 atm

Partial pressure of H_2,

= 0.15 atm

K_p = 1.5\times 10^3 at 400^{\circ} C

As we know,

⇒ K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}

By putting the values, we get

    1.5\times 10^3=\frac{0.20\times (0.15)^3}{pNH_3^2}

        pNH_3^2 = \frac{0.000675}{1.5\times 10^3}

                    =6.7\times 10^{-4} \ atm

                   

3 0
3 years ago
What equation represents the pressure of a gas under ideal conditions?
Leno4ka [110]
P=nRTV
hope this help<span />
8 0
4 years ago
Read 2 more answers
URGENT!!! A solution in which there is very little solute dissolved in a solvent.
ella [17]

Answer:

Is called a diluted solution

Explanation:

Having little solute makes the dissolving process in a large amount of solvent very easy to mix therefore it dilutes in the solvent

4 0
3 years ago
Please help it’s due today I will give brainliest
Thepotemich [5.8K]

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0
3 years ago
A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At
Mazyrski [523]
According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

                                          P</span>₁ / T₁  =  P₂ / T₂     ----- (1)
Data Given;
                  P₁  =  1.5 atm

                  T₁  =  35 °C + 273  =  308 K

                  P₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving Eq. 1 for P₂,

                                   P₂  =  P₁ T₂ / T₁

Putting values,
                                   P₂  =  (1.5 atm × 273 K) ÷ 308 K

                                   P₂  =  1.32 atm
Result:
           As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
5 0
4 years ago
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