Answer:
6.5
Step-by-step explanation:
3.5 + 3
Answer:
well all of these look like a way so we have to use elimination method
A : random number tables : well it has random numbers so X out
B: PHONE NUMBERS: well phone numbers are random so X out
C: USing the internet : totally X out
D: books of random numbers: X out
so none of the above i guess
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

Answer:
False
Step-by-step explanation:
The slope is not constant
The expected value of y when x is equals to 45 in the equation is 35.06
<h3>How to find variable from an equation?</h3>
The equation is given as follows;
y = -2.61x + 152.51
where
- x = variable 1
- y = variable 2
Therefore,
when
x = 45
y = -2.61x + 152.51
y = -2.61(45) + 152.51
y = - 117.45 + 152.51
y = 35.06
learn more on equation here: brainly.com/question/14279419
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