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FinnZ [79.3K]
3 years ago
13

The perimeter of the rectangle below is 90 units. find the length of side vy . write your answer without variables.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0
The picture in the attached figure

we know that
perimeter of a rectangle=2*[base+height]
base=3y+1
height=2y+3
perimeter=90 units
so
90=2*[(3y+1)+(2y+3)]-----> 90=2*[5y+4]----> 10y+8=90----> y=8.2 units

base=3y+1-----> base=3*8.2+1-----> 25.6 units
height=2y+3----> height= 2*8.2+3---> 19.4 units 

the answer is
<span>the length of side vy is (2y+3)-----> 19.4 units</span>

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6.5

Step-by-step explanation:

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3 years ago
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Which of the following is not a way of generating random numbers? A. random number tables B. using phone numbers selected at ran
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Answer:

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A : random number tables : well it has random numbers so X out

B: PHONE NUMBERS: well phone numbers are random so X out

C: USing the internet : totally X out

D: books of random numbers: X out

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3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
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Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
True or False: This table describes a linear function. <br> XY<br> 1 5<br> 2 8<br> 3 10
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Answer:

False

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2 years ago
The fit line equation is Y = -2.61x +152.51, where x is variable 1 and Y is variable 2. According to the equation, what is the e
egoroff_w [7]

The expected value of y when x is equals to 45 in the equation is 35.06

<h3>How to find variable from an equation?</h3>

The equation is given as follows;

y = -2.61x + 152.51

where

  • x = variable 1
  • y = variable 2

Therefore,

when

x = 45

y = -2.61x + 152.51

y = -2.61(45) + 152.51

y = - 117.45 + 152.51

y = 35.06

learn more on equation here: brainly.com/question/14279419

#SPJ1

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