Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 
The sample size needed is 2401.
For the second one 1 mph equals 1.6 km so i’m pretty sure it would be all of them
Answer:
I can't explain here since I can't write numbers.
Step-by-step explanation:
Answer:
The answer is 10m + 7n - 14
Step-by-step explanation:
Q = 7m + 3n
R = 11 - 2m
S = n + 5
T = -m - 3n + 8
[Q - R] + [S - T] is
[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]
Solve the terms in the bracket first
That's
( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)
( 9m + 3n - 11 ) + ( m + 4n - 3)
<u>Remove the brackets</u>
That's
9m + 3n - 11 + m + 4n - 3
<u>Group like terms</u>
9m + m + 3n + 4n - 11 - 3
The final answer is
<h3>
10m + 7n - 14</h3>
Hope this helps you
I'd personally go with A and C, The rest don't make too much sense. Don't count on my answer just yet though.
