To get which design would have maximum area we need to evaluate the area for Tyler's design. Given that the design is square, let the length= xft, width=(120-x)
thus:
area will be:
P(x)=x(120-x)
P(x)=120x-x²
For maximum area P'(x)=0
P'(x)=120-2x=0
thus
x=60 ft
thus for maximum area x=60 ft
thus the area will be:
Area=60×60=3600 ft²
Thus we conclude that Tyler's design is the largest. Thus:
the answer is:
<span>Tyler’s design would give the larger garden because the area would be 3,600 ft2. </span>
Answer:
there is an infinet amount of answers.
Step-by-step explanation:
We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
The answer is (-1,1)
The solution is the point where the two lines cross each other
Hope this helps
