Answer:
An individual whose genotype is heterozygous cannot be for the recessive
Explanation:There are two possible genotypes either homozygous dominant or heterozygous dominant. For a charecter there can be two gene .One is recessive and other one is dominant. In presence of the dominant gene the recessive gene of the same character cannot express . IF recessive gene is homozygous then only it will express .Therefore for the individual it is heterozygous for the dominant
Answer:
light is required to provide energy for photosynthesis
Explanation:
For photosynthesis to take place, it requires the presence of light and chlorophyll. The process has two stages; light and dark stage.
In the light stage, chlorophyll molecules absorb light energy which is used to split water molecules into oxygen and hydrogen atoms. The process is called photolysis.
water→ hydrogen atoms + oxygen.
The hydrogen atoms produced enter the dark stage while oxygen is released in the atmosphere. In the dark stage, carbon dioxide combines with the hydrogen atoms to form simple sugar such as glucose.
Answer:
D
Explanation:
This is because sedimentary rocks are rocks formed by sediments and compaction.
Answer:
If the trait for tall and trait for yellow are recessive: ttyy and ttyy
If the trait for tall is dominant and trait for yellow is recessive: TTyy and TTyy, Ttyy and TTyy
If the trait for tall is recessive and trait for yellow is dominant: ttYY and ttYY, or TtYy and TTYY
If the trait for tall is dominant and trait for yellow is dominant TTYY and TTYY, or TtYy and TTYY
Answer:
option d
Explanation:
Meiosis stage was formerly called the reduction stage involving two divisions; meiosis I and II. After the first stage of meiosis, the ploidy level of each of the daughter cell changes is in an haploid state, meaning here the DNA content has been reduced by half. In humans (2n = 46), who have 23 pairs of chromosomes, the number of chromosomes is reduced by half at the end of meiosis I (n = 23). This haploid state is still maintained by the meiosis II just undergoing the normal mitosis division.
