The gravitational pull of the Sun the interstellar dust attracting heat away from the protosun the process of nuclear fusion the nebular cloud condensing.
The answer is B (The second one). I'm not sure though.
Answer:
B. 59 kg
Explanation:
From the graph you notice that a linear relation in indicated by the line joining the points such that the points on the line represent the data that show a correct relationship in the experiment.
This means that the point outside the line has an error .
This point is the value 59 kg that does not align with other values which are included in the graph.
The net force on the object as described is; 58.84N
Two forces acting on the object are;
- The <em>applied force and the frictional force.</em>
In essence; the frictional force can be evaluated as;
- Frictional force; = coefficient × Weight of object.
- Frictional force = 0.21 × 20 × 9.8.
- Frictional force = 41.16N
- The Net force = Applied force - frictional force
Net Force = 58.84 N.
Read more:
brainly.com/question/94428
Answer:
Depending on the relative position of the Earth the Sun and Neptune in the Earths orbit the distances are;
The closest (minimum) distance of Neptune from the Earth is 29 AU
The farthest (maximum) distance of Neptune fro the Earth is 31 AU
Explanation:
The following parameters are given;
The distance from the Earth to the Sun = 1 AU
The distance of Neptune from the Earth = 30 AU
We have;
When the Sun is between the Earth and Neptune, the distance is found by the relation;
Distance from the Earth to Neptune = 30 + 1 = 31 AU
When the Earth is between the Sun and Neptune, the distance is found by the relation;
Distance from the Earth to Neptune = 30 - 1 = 29 AU
Therefore, the closest distance from Neptune to the Earth in the Earth's Orbit is 29 AU
The farthest distance from Neptune to the Earth in the Earth's orbit is 31 AU.
