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Nookie1986 [14]

3 years ago

5

What is the least force you could exert on the refrigerator to move it?

1 answer:

Ulleksa [173]3 years ago

8 0

<span>If the refrigerator weights 1365 and you are not exerting any vertical force on it, then the normal force is also 1365N. so Fn=1365

Fsf = Static frictional force = (coefficient of static friction) * (Normal force)

So the least for you could exert to move it is equal to the Fsf.
Fsf = (0.49)(1365N)</span><span>
</span>

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On Earth, a scale shows that you weigh 585 N. What would the scale read on the Moon (g = 1.60 m/s2)? N

Serggg [28]

Answer:

95.51 N

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8 0

2 years ago

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is

kodGreya [7K]

Answer:

$\frac{T_t}{T_c} = 1.32$

Explanation:

The torque applied on an object can be calculated by the following formula:

$T = Fr$

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

$T_c = Fr_c\\$

For truck wheel:

$T_t = Fr_t$

Dividing both:

$\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}$

for the same force applied on both wheels:

$\frac{T_t}{T_c} = \frac{r_t}{r_c} \\$

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

$\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\$

$\frac{T_t}{T_c} = 1.32$

8 0

3 years ago