Depreciation of 11% per year means that the price is multiplied by 89% (0.89) every year. Do this 11 times or use exponents
Final price:
207000*(0.89^11) = 57446.083
Answer: 37.56
What the fraction 1/100 is saying is it is dividing them 3756 by a 100.
3756/100= 37.56
I think the answer is B.
Hope this helps.
Answer:
8978 grams
Step-by-step explanation:
The equation to find the half-life is:
![N(t)= N_{0}e^{-kt}](https://tex.z-dn.net/?f=N%28t%29%3D%20N_%7B0%7De%5E%7B-kt%7D)
N(t) = amount after the time <em>t</em>
= initial amount of substance
t = time
It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.
or more simply ![N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }](https://tex.z-dn.net/?f=N%28t%29%3D%20N_%7B0%7D%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7Bt_%7Bh%7D%20%7D%20%7D)
= time of the half-life
We know that
= 35,912, t = 14,680, and
=7,340
Plug these into the equation:
![N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }](https://tex.z-dn.net/?f=N%28t%29%20%3D%2035912%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7B14680%7D%7B7340%7D%20%7D)
Using a calculator we get:
N(t) = 8978
Therefore, after 14,680 years 8,978 grams of thorium will be left.
Hope this helps!! Ask questions if you need!!