Answer:
<h2> $1.50</h2>
Explanation:
Given data
power P= 2 kW
time t= 15 min to hours = 15/60= 1/4 h
cost of power consumption per kWh= 10 cent = $0.1
We are expected to compute the cost of operating the heater for 30 days
but let us computer the energy consumption for one day
Energy of heater for one day= 2* 1/4 = 0.5 kWh
the cost of operating the heater for 30 days= 0.5*0.1*30= $1.50
<u><em>Hence it will cost $1.50 for 30 days operation</em></u>
Answer:
1. E=5320.3J
2. E= 1773.45J
3. E=6.76*10^{-21}J
4. E=2.25*10^{-21}J
Explanation:
1. the thermal energy is given by the formula
where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.
2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is
3.
4.
Hope this helps!!
Answer:1.21A
Explanation: E= Ivt
I=?
V=220volts
E=7.2*10^6
t=45mins
Convert t from mins to secs.
T=45*60=2700secs
E=Ivt
I= E/vt
I=720000/220*2700
I= 720000/594000
I=1.21A