Combustion is and example of an oxidation reaction to burning/high energy conversion.
For this case, the first thing we are going to do is define a reference system.
We define the vertical axis of the reference system, pointing upwards.
Therefore, doing summation of forces in vertical direction we have:
Then, since we want the net force to be equal to zero, then:
From here, we clear the force that we must apply on the object:
The positive sign means that the force points upwards.
Answer:
to create a net force of zero on the object you must apply:
33 Newton upwards.
Answer:
Arranging the events of the earliest stellar formation in sequential order, we get -
3. The big bang occurs. --> 2. Pockets of elements in higher concentrations begin experiencing greater gravitational force. --> 1. Hydrogen atoms shed their electrons and fuse together to form larger helium atoms. --> 4. Hydrogen and helium disperse into the universe in uneven concentrations. --> 6. The gas clouds begin reducing in volume, which leads to increases in density, pressure, and temperature. --> 5. The temperature of gas clouds surpasses 14 million Kelvin.
Correct Order : Option 3, 2, 1, 4, 6, 5
Explanation:
The evolution in Stellar is the process of evolution through which a star which the stellar body changes its morphology over the course of time. All stars being the stellar body are created from collapsing clouds of gas and dust. These collapsing cloud of gas and dust are called nebulae or molecular clouds.
The collapse occurs with gravitational collapse of cool, dense molecular clouds. When the cloud collapses, fragments are formed of smaller regions. These fragments then contract to form stellar cores.
The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy <em>PE</em> :
<em>PE</em> = <em>m g h</em>
<em>PE</em> = (2.0 kg) (9.8 m/s²) (3.0 m)
<em>PE</em> = 58.8 J
Energy is conserved throughout the block's descent, so that <em>PE</em> at the top of the curve is equal to kinetic energy <em>KE</em> at the bottom. Solve for the velocity <em>v</em> :
<em>PE</em> = <em>KE</em>
58.8 J = 1/2 <em>m v</em> ²
117.6 J = (2.0 kg) <em>v</em> ²
<em>v</em> = √((117.6 J) / (2.0 kg))
<em>v</em> ≈ 7.668 m/s ≈ 7.7 m/s
Answer:
<h2>121ohms</h2>
Explanation:
Formula used for calculating power P = current * voltage
P = IV
From ohms law, V = IR where R is the resistance. Substituting V = IR into the formula for calculating power, we will have;
P = IV
P =(V/R)V
P = V²/R
Given parameters
Power rating of the bulb P = 100 Watts
Source voltage V = 110V
Required
Resistance of the bulb R
Substituting the given parameters into the formula for calculating power to get Resistance R;
P = V²/R
100 = 110²/R
R = 110²/100
R = 110 * 110/100
R = 12100/100
R = 121 ohms
<em>Hence, the resistance of this bulb is 121 ohms</em>