Answer:
unloosen the tight attire parts,open all windows for better air circulation,if he/she does not react place your hands on the chest and press gently three times per interval while giving them air through the mouth CPR then when they react place them to lie horizontal face sideways
<h2>
Answer:</h2>
143μH
<h2>
Explanation:</h2>
The inductance (L) of a coil wire (e.g solenoid) is given by;
L = μ₀N²A / l --------------(i)
Where;
l = the length of the solenoid
A = cross-sectional area of the solenoid
N= number of turns of the solenoid
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
<em>From the question;</em>
N = 183 turns
l = 2.09cm = 0.0209m
diameter, d = 9.49mm = 0.00949m
<em>But;</em>
A = π d² / 4 [Take π = 3.142 and substitute d = 0.00949m]
A = 3.142 x 0.00949² / 4
A = 7.1 x 10⁻⁵m²
<em>Substitute these values into equation (i) as follows;</em>
L = 4π x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209 [Take π = 3.142]
L = 4(3.142) x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209
L = 143 x 10⁻⁶ H
L = 143 μH
Therefore the inductance in microhenrys of the Tarik's solenoid is 143
Answer:
The answer is 15000kgms^-2
Explanation:
Actually here we are using the formula F=ma
To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:
Where,
h = Height
= Density
g = Gravity
Our values are
density of water at normal conditions
h = 7.3m
PART A) Replacing these values to find the total pressure difference we have to
In this way the pressure change would be subject to
PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,
Therefore the high which could a faucet be before no water would flow from it is 21.42m
Answer:
volume is 700 mL
Explanation:
pressure = 2 atm
volume = 350 mL = 0.350 L
to find out
volume
solution
we will apply here equation that is
P1×V1 = P2×V2 ..............1
here P1 = 2 and V1 = 0.350 and P2 = 1 for standard atmospheric pressure
so put all value here in equation 1 and get V2 volume
2 × 0.350 = 1 × V2
V2 = 0.700 L
V2 = 700 mL
so volume is 700 mL
