Given:
The force of attraction is F = 48.1 N
The separation between the charges is

Also, the magnitude of charge q1 = q2 = q.
To find the magnitude of charge.
Explanation:
The magnitude of charge can be calculated by the formula

Here, k is the Coulomb's constant whose value is

On substituting the values, the magnitude of charge will be

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.
Answer:
B.) “Shininess” should be explained as “Light bounces off the moving electrons.”
Explanation:
Answer:
D) quadruple.
Explanation:
Assuming the same constant acceleration a in both cases, as we have as givens the acceleration a, the distance d, and the initial velocity v, we can use the following kinematic equations in order to compare the distances:
vf² - v₀² = 2*a*d
As the final state of the car is at rest, the final velocity vf, is 0.
⇒ - v₀² = 2*(-a)*d ⇒ d =v₀² / 2*a
1) initial velocity v₀
d₁ = v₀² / 2 a
2 ) initial velocity 2*v₀
⇒ d₂ = (2*v₀)² / 2*a = 4*v₀² / 2*a ⇒ d₂ = 4* (v₀² / 2*a)
⇒ d₂ = 4* d₁
As the equation shows, the distance required to stop, if the initial velocity were doubled, the distance required to stop would quadruple.