Question

A gas bottle contains 7.86×10^23 Oxygen molecules at a temperature of 327.0 K.

Answer 1

Answer:

1.  E=5320.3J

2. E= 1773.45J

3. E=6.76*10^{-21}J

4. E=2.25*10^{-21}J

Explanation:

1. the thermal energy is given by the formula

$E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J$

where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.

2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

$E_1=\frac{1}{2}NK_BT=1773.45J$

3.

$E=\frac{3}{2}K_BT=6.76*10^{-21}J$

4.

$E=\frac{1}{2}K_BT=2.25*10^{-21}J$

Hope this helps!!