Ask question

Ask question

All categories

3 years ago

15

Edward and his family are sightseeing. They walk two blocks north, four blocks west, and two blocks south. All together, they've

walked ______ blocks and have a total displacement (magnitude only) of four blocks

2 answers:

riadik2000 [5.3K]3 years ago

6 0

consider east-west direction along x-axis and north-south direction along Y-axis

A = displacement in north direction = 2 j

B = displacement in west direction = - 4 i

C = displacement in south direction = - 2 j

total distance travelled is given as

Distance = |A| + |B| + |C| = 2 + 4 + 2 = 8 blocks

displacement is given as

displacement = A + B + C

displacement = 2 j - 4 i - 2 j

displacement = - 4 i

hence the displacement is 4 blocks in west direction.

magnitude of displacement = 4 blocks

they've walked _8 blocks_____ blocks and have a total displacement (magnitude only) of four blocks

svet-max [94.6K]3 years ago

3 0

6 blocks
i hope that this helped

You might be interested in

How long does it take to produce a star?

Reika [66]

Answer: From the moment the first gas cloud begins to compress until the star is formed and glows like the Sun, the process of star creation takes around a million years. Planets and other objects circle the central star using the remaining material from the star's formation.

Explanation:

3 0

3 years ago

Read 2 more answers

A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Svet_ta [14]

Answer:

The speed is $\sqrt{2}v_{0}$ .

(a) is correct option.

Explanation:

Given that,

Potential difference $V= V_{0}$

Speed $v = v_{o}$

If it were accelerated instead

Potential difference $V'=2V_{0}$

We need to calculate the speed

Using formula of initial work done on proton

$W = q V$

We know that,

$\Delta W=\Delta K.E$

$q V=\dfrac{1}{2}mv^2$

Put the value into the formula

$q V_{0}=\dfrac{1}{2}mv_{0}^2$

$v_{0}^2=\dfrac{2qV_{0}}{m}$ ....(I)

If it were accelerated instead through a potential difference of $2 V_{0}$ , then it would gain a speed will be given as :

Using an above formula,

$v_{0}'^2=\dfrac{2qV_{0}}{m}$

Put the value of $V_{0}$

$v_{0}'^2=\dfrac{2q\times2V_{0}}{m}$

$v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}$

$v_{0}'=\sqrt{2}v_{0}$

Hence, The speed is $\sqrt{2}v_{0}$ .

6 0

3 years ago

A model rocket fired vertically from the ground ascends with a constant vertical acceleration of 52.7 m/s2 for 1.41 s. its fuel

olya-2409 [2.1K]

For rectilinear motions, derived formulas all based on Newton's laws of motion are formulated. The equation for acceleration is

a = (v2-v1)/t, where v2 and v1 is the final and initial velocity of the rocket. We know that at the end of 1.41 s, the rocket comes to a stop. So, v2=0. Then, we can determine v1.

-52.7 = (0-v1)/1.41
v1 = 74.31 m/s

We can use v1 for the formula of the maximum height attained by an object thrown upwards:

Hmax = v1^2/2g = (74.31^2)/(2*9.81) = 281.42 m

The maximum height attained by the model rocket is 281.42 m.

For the amount of time for the whole flight of the model rocket, there are 3 sections to this: time at constant acceleration, time when it lost fuel and reached its maximum height and the time for the free fall.

Time at constant acceleration is given to be 1.41 s. Time when it lost fuel covers the difference of the maximum height and the distance travelled at constant acceleration.

2ax=v2^2-v1^2
2(-52.7)(x) = 0^2-74.31^2
x =52.4 m (distance it covered at constant acceleration)
Then. when it travels upwards only by a force of gravity,
d = v1(t) + 1/2*a*t^2
281.42-52.386 = (0)^2+1/2*(9.81)(t^2)
t = 6.83 s (time when it lost fuel and reached its maximum height)

Lastly, for free falling objects, the equation is
t = √2y/g = √2(281.42)/9.81 = 7.57 s

Therefore, the total time= 1.41+6.83+7.57 = 15.81 s

6 0

3 years ago

This graph shows a ball rolling from A to G. The ball starts at point A and rolls to point G.

Lerok [7]

11. B

12. A

13. D

14. The ball burnt off energy while rolling, it lost potential energy and couldn't go as high.

4 0

3 years ago

The greatest ocean depths on the Earth are found in the Marianas Trench near the Philippines. Calculate the pressure (in atm) du

frozen [14]

Answer:

$P = 103867260$ atm

Explanation:

The pressure at the bottom of any liquid column is equal to product of density of the liquid , gravitational acceleration constant (g) and height of the water column

Thus, $P = \rho*g*h$

Substituting the given values, we get -

$P = 1029$ kg/m3 $* 9.8$ m/s^2 $*10.3 *1000$ meters

$P = 103867260$ atm

8 0

3 years ago