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prisoha [69]
4 years ago
14

Range of motion is the distance an object can travel when separated from another object. T/F

Physics
2 answers:
Harrizon [31]4 years ago
4 0

The given statement about the range of motion which is also known as the range of travel is false.

Answer: Option 2

<u>Explanation: </u>

The range of motion or the range of travel is distance measure either angularly or linearly. So, the first half of the given statement is true that it is the distance an object can travel. Coming to the second half of the statement, the statement goes wrong.

Here, the separation of the object from another object is being told which not the case in range of motion is. It needs to be constant attachment to establish the range of motion. Example: flexing of knee.

LUCKY_DIMON [66]4 years ago
3 0

Answer: false

Explanation:

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Which material is a composite? A. gold B.silicon C.polycarbonate D.aluminum
sweet [91]

Answer:

I think gold

Explanation:

6 0
3 years ago
The pressure at the bottom of a lake is 300 000 N/m2 more than at the surface of the lake. The lake is fresh water (density = 10
MakcuM [25]

Answer:

h = 30.61 m

Explanation:

In this problem they indicate the pressure at the bottom of the lake and the density of the water, for which they must ask what is the depth of the lake.

The pressure is given by the expression

           P = P_{atm} + rho g h

           P - P_{atm} = rho g h

       

The gauge pressure value is P- P_{atm} = 3 105 N / m²

          h = \frac{P - P_{atm}}{ \rho \ g}

let's calculate

          h = \frac{3 \ 10^5}{1000 \ 9.8}

          h = 30.61 m

5 0
3 years ago
Please I really need help with this one
bixtya [17]
Cutting pepper and onions
7 0
3 years ago
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

7 0
3 years ago
A third class lever that is 5cm away from the fulcrum, and 20cm away from the fulcrum?
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8 0
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