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3 years ago

Which statement is true about vectors?

2 answers:

5 0

Vectors need direction and magnitude to exist, otherwise, it becomes scalars that do not require direction to be expressed.

eg - Velocity is a vector as it needs direction, but speed is scalar and does not need direction

hope this helps

erica [24]3 years ago

3 0

Answer:

a. All quantities in physics are not vectors. b. A vector may have either magnitude or direction. c. The vector's length should be proportional to its magnitude. d. Two vectors can be added only if they have the same direction.

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A cable weighing 0.6 pounds per foot is attached to a small 70-pound robot, and then the robot is lowered into a 50-foot deep we

Sav [38]

Answer:

4600 ft.Ibs

Explanation:

Work done by the robot in climbing to the top of the well = work done in carrying the cable and itself + work done in carrying about average half the mass of the cable attached to the robot

Now work done = Force × distance = (( 70 +7 ) × 50 ft) + (( 0.6 × 50 ft) × 25 ) = 3850 + 750 = 4600 ft.Ibs

8 0

4 years ago

A 1613 kg car moves with a velocity of 9 m/s. What is its kinetic energy?

ryzh [129]

We Know,

K.E. = 1/2 mv²

K.E. = 1/2 (1613)(9)²

K.E. = 1/2 * 1613*81

K.E. = 65326.5 Kgm/s

4 0

4 years ago

*Urgent* I WILL GIVE BRAINLIEST

Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0

3 years ago

Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g

tekilochka [14]

Answer: a) It will take more time to return to the point from which it was released

Explanation: To determine how long it takes for the ball to return to the point of release and considering it is a free fall system, we can use the given formula:

$d=v_{0}.t + \frac{1}{2} .a.t^{2}$ , where:

d is the distance the ball go through;

v₀ is the initial velocity, which is this case is 0 because he releases the ball;

a is acceleration due to gravity;

t is the time necessary for the fall;

Suppose <em>h</em> is the height from where the ball was dropped.

On Earth:

h=0.t + $\frac{1}{2}.10.t^{2}$

h = 5t²

$t_{T}$ = $\sqrt{\frac{h}{5} }$

On the other planet:

h = 0.t + $\frac{1}{2}.30.t^{2}$

h = 15.t²

$t_{P}$ = $\sqrt{\frac{h}{15} }$

Comparing the 2 planets:

$\frac{t_{T} }{t_{P} } = \frac{\sqrt{\frac{h}{5} } }\sqrt{{\frac{h}{15} } }$

$\frac{t_{T} }{t_{P} }$ = $\sqrt{3}$ or $t_{T} = \sqrt{3}.t_{P}$

Comparing the two planets, on the massive planet, it will take more time to fall the height than on Earth. In consequence, it will take more time to return to the initial point, when it was released.

5 0

3 years ago

10 joules of work (energy) is required to transfer 2 coulombs of charge from X to Y. What is the potential difference between th

ValentinkaMS [17]

Answer:

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

4 0

3 years ago