Answer:
Kinetic energy = (1/2) (mass) (speed²)
Original KE = (1/2) (1430 kg) (7.5 m/s)² = 40,218.75 joules
Final KE = (1/2) (1430 kg) (11.0 m/s)² = 86,515 joules
Work done during the acceleration = (40218.75 - 86515) = 46,296.25 joules
Power = work/time = 46,296.25 joules / 9.3 sec = 4,978.1 watts .
Explanation:
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Answer: biotic
Answer
given,
mass of the goalie(m₁) = 70 kg
mass of the puck (m₂)= 0.11 kg
velocity of the puck = 31.5 m/s
elastic collision
170 N
Given in the question that, work a bulldozer can do = 4500 J
We will use trigonometry identity to find the distance bulldozer will travel up the hill
sin(35) = opp/hypo
sin(35) = 15/hypo
hypo = 15/sin(35)
hypo = 26.15m
Formula to use
work done = force × distance
Plug values in the above formula
4500 = force x 26.15
force = 4500/26.15
force = 172.08
force ≈ 170 N
The force per unit length between the two wires is
The magnitude of the force per unit length exerted between two current-carrying wires is given by
where
is the vacuum permeability
are the currents in the two wires
r is the separation between the two wires
For the wires in this problem, we have
r = 2.00 cm = 0.02 m
Substituting into the equation, we find
Learn more about current and magnetic fields:
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1.93 x 10∧3 N
The picture attached shows the calculation