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cestrela7 [59]
3 years ago
15

an astronaut drops a hammer and an egg while standing on the surface of the moon. which one will the surface first?

Physics
2 answers:
elena-s [515]3 years ago
7 0
The two will fall at the same speed and reach the surface at the same time. This is because the two will experience the same gravitational acceleration on the moon. However, on the earth surface the two will land on the surface of the earth at the same time due to air resistance such that the egg will experience a higher air resistance than the hammer. On, the moon, where there is no noticeable atmosphere there is no air resistance on either object and both fall at the same speed. It is also important to note that their mass doesn't affect their speed.
german3 years ago
4 0

Answer:

They both reach at the same time.

Explanation:

Let the time taken by the hammer and egg be T and t respectively.

initial velocity, u = 0 for both

Distance traveled, h = h for both

acceleration due to gravity = g for both

By using second equation of motion,

S = ut + 0.5 at^2

For hammer

h = 0 + 0.5 x g x T^2     .... (1)

For egg

h = 0 + 0.5 x g x t^2     ....(2)

By observing equation (1) and equation (2), the time taken by the hammer and the egg is same.

They both reach at the same time.

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A low-luminosity star has a small and narrow ​<u>habitable zone</u>, whereas a high-luminosity star has a large and wide one.

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1 year ago
A 1000-kilogram car traveling with a velocity of 20. meters per second decelerates uniformly at -5.0 meters per second2 until it
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Answer:

-20000 kgm/s

Explanation:

Impulse: This can be defined as the product of the mass of a body and its change in velocity. The S.I unit of impulse is kgm/s.

Mathematically, impulse can be expressed as

I = m(v-u).............. Equation 1.

Where I = impulse applied to the car to bring it to rest, m = mass of the car, u = initial velocity of the car, v = final velocity of the car.

Given: m = 1000 kg, u = 20 m/s, v = 0 m/s ( to rest)

Substitute into equation 1

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3 0
3 years ago
Find the voltage change when: a. An electric field does 12 J of work on a 0.0001-C charge. b. The same electric field does 24 J
kondaur [170]

Explanation:

Given that,

(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :

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V=\dfrac{12}{0.0001}

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(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :

V=\dfrac{W}{q}

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The Three fission reactions will produce nine neutrons

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